PHP Codeigniter - 如何通过选项选择设置值来创建数据库

时间:2017-01-26 21:05:20

标签: php mysql codeigniter

我尝试使用Rajaongkir API制作送货方式,但我需要在数据库中添加一些包含运费<?php echo $data['rajaongkir']['results'][$k]['costs'][$l]['cost'][0]['value'] ?>的数据 但是,我的数据库中始终显示“0”

这是我的观点

<?php echo form_open('orders/proceed'); ?>
     <select class="form-control">
            <option name="ongkir" selected="" disabled="">Pilih Layanan</option>
            <?php
             for ($l=0; $l < count($data['rajaongkir']['results'][$k]['costs']); $l++) { 
                ?> 

                <?php echo "<option value='".$data['rajaongkir']['results'][$k]['costs'][$l]['cost'][0]['value']."'>" ?>
                Layanan <?php echo $data['rajaongkir']['results'][$k]['costs'][$l]['service'] ?> |
                <?php echo $data['rajaongkir']['results'][$k]['costs'][$l]['cost'][0]['etd'] ?> Hari | Rp. 
                <?php echo $data['rajaongkir']['results'][$k]['costs'][$l]['cost'][0]['value'] ?>
                <?php "</option>"; ?>

            <?php
            }
            ?>

    </select>

这是控制器

$carts = $this->cart->contents();
            $ongkir = $this->input->post('ongkir');

            foreach ($carts as $item) {
                $product = $this->Product->getProductByCode($item['id']);
                $detail['code'] = $item['id'];
                $detail['name'] = $item['name'];
                $detail['price'] = $item['price'];
                $detail['qty'] = $item['qty'];
                $detail['discount_percent'] = $item['options']['discount_percent'];
                $detail['net_price'] = $product['net_price'];
                $detail['weight'] = $item['options']['weight']; 
                $detail['order_id'] = $orderId;
                $detail['ongkir'] = $ongkir;

                $this->Order_detail->create($detail);
            }

这是截图

screenshot

我无法将运费添加到我的价值中。 如何解决它以及那些运费成本值到我的数据库?

0 个答案:

没有答案