Question

我终于解析了所有解析工作，只有一个例外。

以下代码完全按照原样运作

public void GetCurrentSchedule()
    {


        String JSONstring = File.ReadAllText("\\USER\\Schedule\\Schedule.txt");
        RootObject p1 = JsonConvert.DeserializeObject<RootObject>(JSONstring);


        for (int a = i; a <= (i + 3); a++)
        {
            sDay = p1.schedulePeriods[a].day;
            sPeriod = p1.schedulePeriods[a].periodType;
            sStart = p1.schedulePeriods[a].startTime;
            sCancel= p1.schedulePeriods[a].isCancelled;
            sHeat = p1.schedulePeriods[a].heatSetpoint;
            sCool = p1.schedulePeriods[a].coolSetpoint;
            sFan = p1.schedulePeriods[a].fanMode;

            Console.PrintLine("day: {0}", sDay);
            Console.PrintLine("period: {0}", sPeriod);
            Console.PrintLine("start: {0}", sStart);
            Console.PrintLine("Cancel: {0}", sCancel);
            Console.PrintLine("Heat: {0}", sHeat);
            Console.PrintLine("Cool: {0}", sCool);
            Console.PrintLine("Fan: {0}", sFan);
        }

    }

然而，我想要做的是将每个传递分配给稍后按索引号调用的数组。

例如

sDay = p1.schedulePeriods[a].day;

我希望有4个sDay索引，我可以通过另一个类的索引号来调用。

我一直在撞墙试图让这个工作。

有什么想法吗？

Answer 1

我相信你想要这样的东西？

public void GetCurrentSchedule()
{


    String JSONstring = File.ReadAllText("\\USER\\Schedule\\Schedule.txt");
    RootObject p1 = JsonConvert.DeserializeObject<RootObject>(JSONstring);
    string[] sDay = new string[i + 4];//Declare your array here (+4 becuase your for loop goes upto +3)

    for (int a = i; a <= (i + 3); a++)
    {
        sDay[a - i] = p1.schedulePeriods[a].day; // assign the value to  array element (a - i because if i > 0 because arrays start with 0)
        sPeriod = p1.schedulePeriods[a].periodType;
        sStart = p1.schedulePeriods[a].startTime;
        sCancel= p1.schedulePeriods[a].isCancelled;
        sHeat = p1.schedulePeriods[a].heatSetpoint;
        sCool = p1.schedulePeriods[a].coolSetpoint;
        sFan = p1.schedulePeriods[a].fanMode;

        Console.PrintLine("day: {0}", sDay[a - i]); // Call it with index
        Console.PrintLine("period: {0}", sPeriod);
        Console.PrintLine("start: {0}", sStart);
        Console.PrintLine("Cancel: {0}", sCancel);
        Console.PrintLine("Heat: {0}", sHeat);
        Console.PrintLine("Cool: {0}", sCool);
        Console.PrintLine("Fan: {0}", sFan);
    }

}

Answer 2

public List<string> SDays = new List<string>(); // or whatever type     


        //  inside method
        String JSONstring = File.ReadAllText("\\USER\\Schedule\\Schedule.txt");
        RootObject p1 = JsonConvert.DeserializeObject<RootObject>(JSONstring);

        for (int a = i; a <= (i + 3); a++)
        {
            SDays.Add(p1.schedulePeriods[a].day);
            //and so on
        }

致电SDays[index]以从其他班级获得正确的一天

您可能也希望将其更改为更清晰的OOP样式。

C＃将数据传递给数组

2 个答案: