我正在努力将添加到另一个列表的超链接添加到我生成的excel文件中。我试过这样的话:
ws.Cells[1, 1].Formula="HYPERLINK(\"[#]'sheetName'!R4C1\";\"linktext\")"
ws.Cells[1, 1].Formula="HYPERLINK(\"#'sheetName'!R4C1\";\"linktext\")"
ws.Cells[1, 1].FormulaR1C1="HYPERLINK(\"[#]'sheetName'!R4C1\";\"linktext\")"
ws.Cells[1, 1].FormulaR1C1="HYPERLINK(\"#'sheetName'!R4C1\";\"linktext\")"
在excel 365(完全脱机应用程序)中打开生成的excel文件后,我得到的消息是文件中存在错误,并且我使用此超链接公式的所有单元格都是空的。
错误消息是:
we found a problem with some content in FILENAME do you want us to try to recover as much as we can
如何让它发挥作用?
此外,当我手动将相同的公式放入单元格时,它也能正常工作。
完整代码:
using OfficeOpenXml;
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace ExcelHyperlinkTest
{
class Program
{
static void Main(string[] args)
{
MemoryStream excelStream = new MemoryStream();
ExcelPackage excelFile = new ExcelPackage(excelStream);
ExcelWorksheet wsSrc = excelFile.Workbook.Worksheets.Add("src");
ExcelWorksheet wsTgt = excelFile.Workbook.Worksheets.Add("tgt");
wsSrc.Cells[1, 1].Formula = string.Format("HYPERLINK(\"#'{0}'!R{1}C{2}\";\"{3}\")", "tgt", 2, 5, "test"); //FormulaR1C1
excelFile.Save();
excelStream.Position = 0;
using (FileStream file = new FileStream("c:\\linkTest.xlsx", FileMode.Create, System.IO.FileAccess.Write))
{
byte[] bytes = new byte[excelStream.Length];
excelStream.Read(bytes, 0, (int)excelStream.Length);
file.Write(bytes, 0, bytes.Length);
excelStream.Close();
}
}
}
}
答案 0 :(得分:6)
这有效
wsSrc.Cells[1, 6].Value = "test3";
Uri url = new Uri("#'tgt'!B5", UriKind.Relative);
wsSrc.Cells[1, 6].Hyperlink = url;
答案 1 :(得分:0)
如果工作表存在于同一个excel文件中,并且任何人都使用EPPlus库,则以下代码可能会帮助他们:
int rowCount=<your specific row>
ws.Cells[rowCount, 6].Hyperlink = new ExcelHyperLink((char)39 + "Name of your sheet" +
(char)39 + "!A1(specific cell on that sheet)", "Link text");
答案 2 :(得分:0)
这将相对于当前工作簿链接到工作簿(workbookPath)的工作表(sheetName)中的B5,并将链接设置为超链接格式
using (ExcelRange rng = xlsheetSummary.Cells[1, 1])
{
var namedStyle = xlsheetSummary.Workbook.Styles.NamedStyles.FirstOrDefault(o=> o.Name == "HyperLink");
namedStyle.Style.Font.UnderLine = true;
rng.StyleName = namedStyle.Name;
rng.Value = ws.Name;
Uri link = new Uri($"{workbookPath}#'{sheetName}'!B5", UriKind.Relative);
namedStyle.Style.Font.Color.SetColor(Color.Blue);
rng.Hyperlink = link;
}