我正在制作一个四连胜游戏。 但我遇到了问题。我已经能够使游戏工作。但我想知道我是否可以将我的public void fillBoard()和public void presentBoard()移动到另一个类中。这是因为我想让代码更有条理。
package com.company;
public class Main {
public static void main(String[] args)
{
GameMechanics game = new GameMechanics();
game.play();
}
}
package com.company;
import java.util.Scanner;
public class GameMechanics
{
/*
This is my local variables
*/
public Scanner scanner = new Scanner(System.in);
public char token;
public int column;
public int player = 2;
public int turn = 2;
public int count = 0;
public boolean gameRunning = true;
public void play()
{
this.createBoard();
//While gameRunning is true, the methods inside the { } will run, and that's the 4InARow game
while (gameRunning)
{
this.presentBoard();
this.changeTurn();
this.dropToken();
this.gameWon();
}
presentBoard();
}
public void gameWon()
{
this.winConHorizontal();
this.winConVertical();
}
private char[][] board = new char[6][7];
//Creating my board and assign "space" to all the fields in the array.
public void createBoard() {
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 7; j++) {
board[i][j] = ' ';
}
}
}
//Presents the board, it prints the board with |"space"| so it looks more like a gameboard.
public void presentBoard() {
for (int i = 0; i < 6; i++) {
for (int j = 0; j < 7; j++) {
if (j == 0) {
System.out.print("|");
}
System.out.print(board[i][j] + "|");
}
System.out.println();
}
}
public void changeTurn() {
if (this.turn == this.player) {
this.turn = 1;
this.token = 'X';
} else {
this.turn++;
this.token = 'O';
}
}
public void dropToken() {
System.out.println("player " + turn + ": press 1-7 to drop the token");
column = scanner.nextInt() - 1;
//If pressed any intValue outside the board, it will tell you to try again.
if (column >= 7 || column <= -1)
{
System.out.println("place the token inside the bord");
changeTurn();
} else {
//Drops the token and replace it with playerChar.
for (int i = 5; i > -1; i--) {
if (board[i][column] == ' ')
{
board[i][column] = token;
break;
}
}
}
}
public boolean winConHorizontal() {
while (gameRunning) {
for (int i = 0; 6 > i; i ++) {
for (int j = 0; 7 > j; j ++) {
if (board[i][j] == this.token) {
count ++;
} else {
count = 0;
}
if (count >= 4) {
System.out.println("player " + (turn) + " Wins!!!!");
gameRunning = false;
}
}
}
break;
}
return gameRunning;
}
public boolean winConVertical() {
while (gameRunning) {
for (int i = 0; 7 > i; i ++) {
for (int j = 0; 6 > j; j ++) {
if (board[j][i] == this.token) {
count ++;
} else {
count = 0;
}
if (count >= 4) {
System.out.println("player " + (turn) + " Wins!!!!");
gameRunning = false;
}
}
}
break;
}
return gameRunning;
}
}
答案 0 :(得分:2)
一种简单的方法如下:
char[][] board
提取到自己的类中,例如Board
所述类可以公开函数char getField(int index)
BoardPresenter
。所述类应该有一个函数presentBoard(Board board)
,它在内部使用getField(int index)
的{{1}}类。通过这样做,您可以抽象出内部电路板存储机制,同时减少Board
班级的职责数量(参见https://en.wikipedia.org/wiki/Single_responsibility_principle)
答案 1 :(得分:0)
是的,您可以创建另一个类并使用当前类 GameMechanics
扩展它,并在另一个类中定义函数。
注意:这是一种非常简单的平易近人的方式。 否则,如果你管理类似于mvc模型的类和接口会更好,你可以在youtube上搜索mvc structure java。