Question

我的数据格式

{
    "StationID": "1001",
    "StationName": {
      "Zh_tw": "基隆",
      "En": "Keelung"
    },
    "TrainNo": "1281",
    "Direction": 1,
    "TrainClassificationID": "1131",
    "TripLine": 0,
    "EndingStationID": "1025",
    "EndingStationName": {
      "Zh_tw": "新竹",
      "En": "Hsinchu"
    },
    "ScheduledArrivalTime": "22:02:00",
    "ScheduledDepartureTime": "22:04:00",
    "DelayTime": 0,
    "Platform": "",
    "SrcUpdateTime": "2017-01-24T22:14:29+08:00",
    "UpdateTime": "2017-01-24T22:14:40+08:00"
  },

我的代码（Swift 3）

override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "Cell", for: indexPath) as! TableViewCell
    // Configure the cell...
    cell.stationID.text = trainStatusArray[indexPath.row]["StationID"] as? String

    let stationDirect = trainStatusArray[indexPath.row]["Direction"] as? Int
    if stationDirect == 0 {
        cell.stationdirection.text = "順行"
    }else{
        cell.stationdirection.text = "逆行"
    }

    cell.stationtrainNo.text = trainStatusArray[indexPath.row]["TrainNo"] as? String

    let stationTripline = trainStatusArray[indexPath.row]["TripLine"] as? Int
    if stationTripline == 0 {
        cell.stationtripLine.text = "不經山線/海線"
    }else if stationTripline == 1 {
        cell.stationtripLine.text = "山線"
    }else {
        cell.stationtripLine.text = "海線"
    }
    //cell.stationtripLine.text = String(stationTripline!)

    return cell
}

我的问题是如何将StationName，Zh_tw和En传输到TableView单元格？

Answer 1

StationName和EndingStationName都是字典，因此您可以像这样获得Zh_tw的价值。

if let stationName = trainStatusArray[indexPath.row]["StationName"] as? [String:Any], 
   let zhTW = stationName ["Zh_tw"] as? String, let en = stationName ["En"] as? String { 
       cell.stationName.text = zhTW 
}else {
       cell.stationName.text = ""//Set default name
}

同样适用于EndingStationName。

注意：如果您从此词典创建自定义对象数组，则可以通过cellForRowAt方法轻松分配标签文本，而不是使用字典数组。

Answer 2

首先将JSON String转换为Data，然后使用Data再次将Dictionary转换为JSONSerialization表单

Swift 3

func convertToDictionary(text: String) -> [String: Any]? {
    if let data = text.data(using: .utf8) {
        do {
            return try JSONSerialization.jsonObject(with: data, options: []) as? [String: Any]
        } catch {
            print(error.localizedDescription)
        }
    }
    return nil
}

// pass your String JSON 
    let dict = convertToDictionary(text: str)

Swift 2

func convertStringToDictionary(text: String) -> [String:AnyObject]? {
    if let data = text.dataUsingEncoding(NSUTF8StringEncoding) {
        do {
            return try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String:AnyObject]
        } catch let error as NSError {
            print(error)
        }
    }
    return nil
}

从String获取dictonary

let dict= convertStringToDictionary(str)

if let strStationName= result?["EndingStationName"] {

  let zhTW = strStationName["Zh_tw"] as? String  

   cell.stationdirection.text=zhTW 
}

Swift JSON进入TableViewCell

2 个答案: