我正在尝试从图像中提取标题。我设法提取url
,但不知道如何编码提取图像标题。
import requests
from bs4 import BeautifulSoup
def trade_spider(max_pages):
page = 1
while page <= max_pages:
url = 'http://www.gurstree.com.au/s—cars—vans—utes/melbourne/page—' + str(page) + '/c1832013001317'
source_code = requests.get(url)
plain_text = source_code.text
soup = BeautifulSoup(plain_text)
for link in soup.findAll('a', {'class': 'ad—listing_title—link'}):
href = 'http://www.gumtree.com.au/' + link.get('href')
print(href)
page += 1
trade_spider(1)
<a itemprop="url" class="ad-listing__thumb-link" name="1124692138" href="/s-ad/derrimut/cars-vans-utes/2015-toyota-86-coupe-12-month-warranty-/1124692138" data-ref="searchTopAd">
<span id="r-image-TOP_AD-1124692138" title="2015 Toyota 86 Coupe **12 MONTH WARRANTY** Derrimut Brimbank Area Preview" class="j-responsive-image ad-listing__thumb" data-index="1">...</span>
</a>
第一行是href
,但我希望根据突出显示的title
HTML块获取span
。
谢谢!
答案 0 :(得分:0)
link.span.get('title')
使用.
查找下一个span
并获取title
使用regex匹配addribute中的字符串:
import re
soup.find('span', id=re.compile(r'r-image'))