我有这个SQL查询,让我知道客户订购某个产品的时间:
qDebug() << QByteArray::fromHex("ACDC"); // outputs "\xAC\xDC"
我希望得到订购产品1,2,3但从不订购4的客户。
我不能简单地制作SELECT * FROM ps_customer c
INNER JOIN ps_orders o ON (c.id_customer=o.id_customer)
INNER JOIN ps_order_detail od ON(od.id_order=o.id_order)
WHERE od.product_id=1
,但我仍然坚持如何正确构建该查询。
有关信息,数据库结构是基本的Prestashop(1.6.1.4)数据存储区。
这里是SQLFiddle: http://sqlfiddle.com/#!9/dfd65
(我无法添加数据,对SQLFiddle来说太过分了......)
感谢您的帮助:)
答案 0 :(得分:1)
你可以在id_customer
上使用几个dinaminc表连接 select * from (
SELECT id_customer
FROM ps_customer c
INNER JOIN ps_orders o ON c.id_customer=o.id_customer
INNER JOIN ps_order_detail od ON od.id_order=o.id_order
WHERE od.product_id <> 4 ) t1
INNER JOIN (
SELECT id_customer FROM ps_customer c
INNER JOIN ps_orders o ON c.id_customer=o.id_customer
INNER JOIN ps_order_detail od ON od.id_order=o.id_order
WHERE od.product_id in ( 1,2,3)
having count(distinct(od.product_id)) =3
) t2 on t1.id_customer = t2.id_customer
答案 1 :(得分:1)
可能你应该以不同的方式思考
SELECT * FROM ps_customer c
INNER JOIN ps_orders o ON (c.id_customer=o.id_customer)
INNER JOIN ps_order_detail od ON(od.id_order=o.id_order)
WHERE od.product_id IN (1, 2, 3) and c.id_customer NOT IN (select id_customer from ps_orders where product_id IN (4) )