Question

我正在尝试迭代一个列表，以获得一个网站的链接，该网站的子类别各有多个页面。子类别中的第一个链接具有列表中的第一个数字（8），第二个链接具有6个，依此类推。我的最终结果想看起来像这样：

sublinks: 
0   https://messageboards.webmd.com/family-pregnancy/f/relationships/
1   https://messageboards.webmd.com/family-pregnancy/f/parenting/
2   https://messageboards.webmd.com/family-pregnancy/f/pets/
3   https://messageboards.webmd.com/family-pregnancy/f/pregnancy/

尝试迭代for循环的列表：[8,6,5,13,10,16,13,15,4,4,5,7,2,6,6,8,9,8,3 ，8,8,1,6,3,2,15,5,4,2,12,18,5,2]

import bs4 as bs
import urllib.request
import pandas as pd
import urllib.parse
import re


#source = urllib.request.urlopen('https://messageboards.webmd.com/').read()
source = urllib.request.urlopen('https://messageboards.webmd.com').read()
soup = bs.BeautifulSoup(source,'lxml')


df = pd.DataFrame(columns = ['link'],data=[url.a.get('href') for url in soup.find_all('div',class_="link")])
lists =[]
lists2=[]
lists3=[]
page_links = []


for i in range(0,33):
    link = (df.link.iloc[i])
    req = urllib.request.Request(link)
    resp = urllib.request.urlopen(req)
    respData = resp.read()
    temp1=re.findall(r'Filter by</span>(.*?)data-pagedcontenturl',str(respData))
    temp1=re.findall(r'data-totalitems=(.*?)data-pagekey',str(temp1))[0]
    pageunm=round(int(re.sub("[^0-9]","",temp1))/10)
    lists.append(pageunm)

for j in lists:
    for x in range(1, j+1):
        url_pages = link + '#pi157388622=' + str(j)
        page_links.append(url_pages)

第一次迭代的最终结果看起来像这样：

https://messageboards.webmd.com/family-pregnancy/f/relationships/#pi157388622=1
https://messageboards.webmd.com/family-pregnancy/f/relationships/#pi157388622=2
https://messageboards.webmd.com/family-pregnancy/f/relationships/#pi157388622=3
https://messageboards.webmd.com/family-pregnancy/f/relationships/#pi157388622=4
https://messageboards.webmd.com/family-pregnancy/f/relationships/#pi157388622=5
https://messageboards.webmd.com/family-pregnancy/f/relationships/#pi157388622=6
https://messageboards.webmd.com/family-pregnancy/f/relationships/#pi157388622=7
https://messageboards.webmd.com/family-pregnancy/f/relationships/#pi157388622=8

Answer 1

如果你的问题是你不能让迭代从1开始到初始列表中的数字（在代码示例之外），那么你可以尝试这样的事情：

sub_links = [8, 6, 5, 13, 10, 16, 13, 15, 4, 4, 5, 7, 2, 6, 6, 8, 9, 8, 3, 8, 8, 1, 6, 3, 2, 15, 5, 4, 2, 12, 18, 5, 2]
for length in sub_links:
    for number in range(1, length + 1):
        print(number, end=' ')
    print()

目前打印每行所需的所有数字。调整内部for循环体以将数字附加到您的链接上，然后您就可以拥有它。

如果您的问题与其他内容有关，那么您需要更清楚 - 我建议您只包含无效的代码并解释问题所在。

从列表循环迭代

1 个答案: