我正在为密码验证器编写类的程序。我需要密码至少6个字符,但我也将其限制为最多10个(不是必需的但是想要)。
该程序运行良好,我的其他验证工作,直到我尝试添加超过10个字符的密码。我可以通过并重新输入一个新密码,我收到的消息是它现在是一个有效的密码。但后来我得到了以下错误:
运行时检查失败#2 - 变量'password'周围的堆栈已损坏。
如果设置宽度,我可以解决错误,但我知道这不是处理它的正确方法。另外我认为通过设置宽度,用户将无法输入除该大小以外的任何内容。
这是我的代码:
#include <iostream>
#include <iomanip>
#include <cstring>
#include <cctype>
using namespace std;
//Function prototypes
bool validatePassword(char *); //function to test pw requirements
bool validateUppercase(char *); //function to test for upper case value
bool validateLowercase(char *); //function to test for lowercase value
bool validateNumber(char *); //function to test for a number value
bool validateLength(char *); //function to test for password length
int main()
{
//Variabes
char password[11]; //set the maximum number of char for password include the end delimiter
int size; //size of the array
//Prompt user to enter a password based on criteria
cout << "Please enter a password that meets the following criteria: \n";
cout << "1. A minimum of 6 characters up to a max of 10. \n";
cout << "2. Contains atleast one uppercase and one lowercase character. \n";
cout << "3. Contains atleast one number. \n\n";
//cout << "****Please note if you have more the 10 characters \n";
//cout << " the program will only accept the first 10***\n";
cout << "\nPlease enter your password: ";
cin >> password;
//cin >> setw(10) >> password; //set this so I would not get a runtime error
size = strlen(password); //determines the length of the password
do
{
while (!validatePassword(password)) //if the functions returns a false value
{
cout << "\nYour password does not meet the requirements. ";
cout << "\nEnter a new password: ";
cin >> password;
size = strlen(password);
}
} while (size > 10);
if (validatePassword(password))
{
cout << "\nYour password " << password << " meets the requirements. \n"; //if the function returns a true value
}
system ("pause");
return 0;
}
//This function calls the other validation functions
bool validatePassword(char *pass)
{
int size = strlen(pass);
return (validateLength(pass) && validateUppercase(pass) && validateLowercase(pass) && validateNumber(pass) == true);
}
//This function validates the length of the password
bool validateLength (char *pass)
{
int size = strlen(pass);
if (size >= 6 && size < 10)
return true;
else
{
cout << "\n\nThe password you entered either contained to little or to many characters.";
cout << "\nA minimum of 6 characters to a maximum of 10 is required.";
return false;
}
}
//This function checks to see if the password contains an uppercase char
bool validateUppercase(char *pass)
{
int size = strlen(pass);
for (int count = 0; count < size; count++)
{
if (isupper(pass[count]))
return true;
}
cout << "\n\nThe password must contain at least one uppercase character. ";
return false;
}
//This function checks to see if the password contains an lowercase char
bool validateLowercase(char *pass)
{
int size = strlen(pass);
for (int count = 0; count < size; count++)
{
if (islower(pass[count]))
return true;
}
cout << "\n\nThe password must contain at least one lowercase character. ";
return false;
}
//This function checks to see if the password contains an number char
bool validateNumber(char *pass)
{
int size = strlen(pass);
for (int count = 0; count < size; count++)
{
if (isdigit(pass[count]))
return true;
}
cout << "\n\nThe password must contain at least one number. " ;
return false;
}
答案 0 :(得分:2)
使用cstrings,运算符<<
将读取一个字符串,并在缓冲区的末尾自动附加空字节字符,如果有足够的空间。
你分配一个11的缓冲区,所以当输入的密码高于10时,终止字符串的空字节不会出现,导致strlen
等问题。实际上,strlen
所做的只是读取输入并递增计数器直到遇到\0
。
您现在有两个选择:
cstring
并增加缓冲区的大小(足够高以避免意外),string
类,这是一个能够动态增加的char数组(强烈推荐,here is a link to get started)。 另外,关于代码:你有很多不必要的东西。例如:
do
{
while (!validatePassword(password)) //if the functions returns a false value
{
cout << "\nYour password does not meet the requirements. ";
cout << "\nEnter a new password: ";
cin >> password;
size = strlen(password);
}
} while (size > 10);
if (validatePassword(password))
{
cout << "\nYour password " << password << " meets the requirements. \n"; //if the function returns a true value
}
可以替换为:
while (!validatePassword(password))
{
cout << "\nYour password does not meet the requirements. ";
cout << "\nEnter a new password: ";
cin >> password;
}
cout << "\nYour password " << password << " meets the requirements. \n";
validatePassword
调用validateLength
来检查strlen(pass) <= 10
,只有在密码正确时才能退出第一个循环。
另一个改进是将密码的大小传递给您的函数,以避免在任何地方调用strlen
(在C中通常使用char *
参数传递大小)。