Question

我正试图找到一种方法来禁用我的python代码中记录此错误。该程序似乎实际运行正常，搜索功能只返回一个包含数十个属性的json对象，每当找到一个无法打印的字符时，它将打印出返回的数千个json对象到控制台。

我在一个try块中包含了有罪代码（下面），但它没有改变任何东西。

try:
    results = api.search(query)
    print('Station hits: ', len(results['station_hits']), '\nSong hits: ', len(results['song_hits']), '\nArtist hits: ', len(results['artist_hits']), '\nAlbum hits: ', len(results['album_hits'])).encode('ascii', 'ignore')
except UnicodeEncodeError:
    pass

以下是打印到控制台的错误。（没有前面引用的文本）

--- Logging error ---
Traceback (most recent call last):
  File "C:\Users\670854\AppData\Local\Programs\Python\Python36-32\lib\logging\__init__.py", line 989, in emit
    stream.write(msg)
  File "C:\Users\670854\AppData\Local\Programs\Python\Python36-32\lib\encodings\cp1252.py", line 19, in encode
    return codecs.charmap_encode(input,self.errors,encoding_table)[0]
UnicodeEncodeError: 'charmap' codec can't encode character '\u2117' in position 108194: character maps to <undefined>
Call stack:
  File "gpm.py", line 247, in <module>
    main()
  File "gpm.py", line 181, in main
    results = api.search(query)
  File "C:\Users\670854\AppData\Local\Programs\Python\Python36-32\lib\site-packages\gmusicapi\clients\mobileclient.py", line 1806, in search
    res = self._make_call(mobileclient.Search, query, max_results)
  File "C:\Users\670854\AppData\Local\Programs\Python\Python36-32\lib\site-packages\gmusicapi\clients\shared.py", line 84, in _make_call
    return protocol.perform(self.session, self.validate, *args, **kwargs)
  File "C:\Users\670854\AppData\Local\Programs\Python\Python36-32\lib\site-packages\gmusicapi\protocol\shared.py", line 243, in perform
    log.debug(cls.filter_response(parsed_response))

Answer 1

追溯等显示：无法使用cp1252对u“\ u2117”进行编码，这并不奇怪，请改用utf8。

Python 3.6中的UnicodeEncodeError

1 个答案: