我现在已经在这个任务上工作了一段时间,而且我很难插入到我的非STL列表中。代码将成功编译,但每次插入到我的列表中时会出现段错误。以下是一些相关代码。
tripper.h:
class adjNode
{
public:
int vertex;
int weight;
adjNode(int v, int w) : vertex(v), weight(w) { }
adjNode() { }
};
tripper.cpp:
Tripper::Tripper(Road *roads, int numRoads, int size)
{
List <adjNode> adjList[numRoads];
for (int i=0; i<numRoads; i++) //Doesn't work with either line
{
adjList[roads[i].city1].push_back(adjNode(roads[i].city2, roads[i].distance));
//adjList[0].push_back(adjNode(2, 15)); //Really it's nothing but 3 integers involved
}
for (int i=0; i<9; i++)
{
for (List<adjNode>::iterator itr = adjList[i].begin(); itr != adjList[i].end(); itr++)
{
cout << "There is an edge going from " << i << " to " << (*itr).vertex;
cout << " with a weight of " << (*itr).weight << endl;
}
}
} // Tripper()
list.h:
void push_back( const Object & x )
{
insert( end( ), x );
}
iterator insert( iterator itr, const Object & x )
{
Node *p = itr.current;
theSize++;
return iterator( p->prev = p->prev->next = new Node( x, p->prev, p ) );
}
节点
struct Node {
Object data;
Node *prev;
Node *next;
Node( const Object & d = Object( ), Node * p = NULL, Node * n = NULL )
: data( d ), prev( p ), next( n )
{
}
};
答案 0 :(得分:1)
返回迭代器(p-&gt; prev = p-&gt; prev-&gt; next = new Node(x,p-&gt; prev,p));
如果p-&gt; prev为NULL,则该行将崩溃。
答案 1 :(得分:0)
使用笔和纸,并为指针操作绘制箭头。
将不同行上的操作分开,以便能够表达您的意图并更轻松地调试代码。