我有一个混合数组，我需要按字母顺序排序，然后按数字
排序[Ab-1,Ab-5,Ab-11,ab-101,ab-100,ab-10,ab-12,ab-3,ab-21]
根据代码，我得到以下输出
ab-1 ab-5 ab-11 ab-101 ab-100 ab-10 ab-12 ab-3 ab-21
根据代码，默认情况下，第三列单独显示活动和非活动。但我想要第一列（ID）也将它排序为：
ab-1
ab-2
ab-3
ab-5
ab-10
ab-11
ab-12
ab-100
ab-101....
请帮助
<!DOCTYPE HTML>
<html lang="en-US">
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script>
// Fetch the values from json
$(document).ready(function() {
$.getJSON("dynamic_content_values1.json",
/* sort starts for Active and Inactive */
function(result_1) {
function sortJSON(data, key) {
return data.sort(function (a, b) {
var x = a[key];
var y = b[key];
return ((x < y) ? -1 : ((x > y) ? 1 : 0));
});
}
sorting_active_and_inactive = sortJSON(result_1, 'flag');
/* sort End for Active and Inactive*/
$.each(sorting_active_and_inactive,function(i, field) {
var status = field.flag;
if (status == 'N') {
status = 'Active';
} else {
status = 'Inactive';
}
var data = '<tr><td><a href="#">' + field.first_column + '</a></td><td>' + field.summary + '</td><td>' + status + '</td></tr>';
$("#resultBody").append(data);
});
});
//******************************************* Starting CODE for Sorting the Active/In-Active Columns *******************************************
function sortTable(table, col, reverse) {
var tb = table.tBodies[0], // use `<tbody>` to ignore `<thead>` and `<tfoot>` rows
tr = Array.prototype.slice.call(tb.rows, 0), // put rows into array
i;
reverse = -((+reverse) || -1);
tr = tr.sort(function (a, b) { // sort rows
return reverse // `-1 *` if want opposite order
* (a.cells[col].textContent.trim() // using `.textContent.trim()` for test
.localeCompare(b.cells[col].textContent.trim())
);
});
for(i = 0; i < tr.length; ++i) tb.appendChild(tr[i]); // append each row in order
}
function makeSortable(table) {
var th = table.tHead, i;
th && (th = th.rows[0]) && (th = th.cells);
if (th) i = th.length;
else return; // if no `<thead>` then do nothing
while (--i >= 0) (function (i) {
var dir = 1;
th[i].addEventListener('click', function () {sortTable(table, i, (dir = 1 - dir))});
}(i));
}
function makeAllSortable(parent) {
parent = parent || document.body;
var t = parent.getElementsByTagName('table'), i = t.length;
while (--i >= 0) makeSortable(t[i]);
}
window.onload = function () {makeAllSortable();};
//************************************************** Ending CODE for Sorting the Active/In-Active Columns *********************************
});
function showabc() {
document.getElementById('container1').style.display = "block";
}
</script>
</head>
<body>
<div class="" id="container1">
<table>
<thead>
<tr>
<th><b>ID</b></th>
<th><b>Summary</b></th>
<th>Status</th>
</tr>
</thead>
<tbody id="resultBody" style="cursor: move">
</tbody>
</table>
</div>
<div class="containerPopup1"><div id="abc1" style="height: 1400px;"></div></div>
<div class="containerPopup"><div id="abc2" style="height: 2700px;"></div></div>
</body>
</html>
请找到示例json数组结构：
[ {
"first_column": "AB-1",
"summary": "AB-1 Summary",
"flag": "N"
}, {
"first_column": "AB-11",
"summary": "AB-11 Summary",
"flag": "N"
},{
"first_column": "AB-12",
"summary": "AB-12 Summary",
"flag": "Y"
},{
"first_column": "AB-10",
"summary": "AB-10 Summary",
"flag": "Y"
},{
"first_column": "AB-100",
"summary": "AB-100 Summary",
"flag": "Y"
},{
"first_column": "AB-101",
"summary": "AB-101 Summary",
"flag": "N"
},{
"first_column": "AB-2",
"summary": "AB-2 Summary",
"flag": "Y"
},{
"first_column": "AB-3",
"summary": "AB-3 Summary",
"flag": "Y"
},{
"first_column": "AB-21",
"summary": "AB-21 Summary",
"flag": "Y"
},{
"first_column": "AB-210",
"summary": "AB-210 Summary",
"flag": "Y"
},{
"first_column": "AB-211",
"summary": "AB-211 Summary",
"flag": "Y"
},{
"first_column": "AB-5",
"summary": "AB-5 Summary",
"flag": "N"
}]
答案 0 :(得分：0)
您可以将字符串拆分为mysql_query("
INSERT into `new_table` (`hash`,`first_visit`, `country`, `browser`) values ('$hash',CURDATE(), '$details->geoplugin_countryCode','$_SERVER[HTTP_USER_AGENT]');
INSERT into `behaviour` (`hash`,`page`,`url`,`entry`, `ref`) values ('$hash','$page','$url','$entry', '$ref')
");
，并将字母部分视为字符串，将数字视为数字。
'-'var array = [{ notificationID: "AB-1", summary: "AB-1 Summary", flag: "N" }, { notificationID: "AB-11", summary: "AB-11 Summary", flag: "N" }, { notificationID: "AB-12", summary: "AB-12 Summary", flag: "Y" }, { notificationID: "AB-10", summary: "AB-10 Summary", flag: "Y" }, { notificationID: "AB-100", summary: "AB-100 Summary", flag: "Y" }, { notificationID: "AB-101", summary: "AB-101 Summary", flag: "N" }, { notificationID: "AB-2", summary: "AB-2 Summary", flag: "Y" }, { notificationID: "AB-3", summary: "AB-3 Summary", flag: "Y" }, { notificationID: "AB-21", summary: "AB-21 Summary", flag: "Y" }, { notificationID: "AB-210", summary: "AB-210 Summary", flag: "Y" }, { notificationID: "AB-211", summary: "AB-211 Summary", flag: "Y" }, { notificationID: "AB-5", summary: "AB-5 Summary", flag: "N" }];
array.sort(function (a, b) {
function split(s) { return s.split('-'); }
var aa = split(a.notificationID),
bb = split(b.notificationID);
return aa[0].localeCompare(bb[0]) || aa[1] - bb[1];
});
console.log(array);
答案 1 :(得分：-1)
var a=[ {
"LIST": "14:NATURAL RESOURCES"
},
{
"LIST": "7:DIVERSITY IN LIVING ORGANISMS"
},
{
"LIST": "3:ATOMS AND MOLECULES"
},
{
"LIST": "10:GRAVITATION"
},
{
"LIST": "6:TISSUES"
}]
var c=a.sort(function(a,b){
let aa=a.LIST,bb=b.LIST;
return parseInt(aa.split(":")[0]-bb.split(":")[0])
})
console.log(c)