Question

我正在尝试将数据从数据库打印到html表。我希望我的桌子像这样：

| username | studio APEX | studio CANVAS | studio ORBIT |
+----------+-------------+---------------+--------------+
| Aaron    |       x     |       x       |              |
| Adel     |             |               |       x      |
| John     |       x     |       x       |              |
| James    |       x     |       x       |              |
| Kate     |             |               |       x      |
| Peter    |       x     |               |              |

工作室名称取自数据库。我得到的是查询：

$sql2 = '
            select
              p2.proc_leader as username,
                   max(case when studio = "APEX" then "x" else "" end) as APEX,
                   max(case when studio = "BASECAMP" then "x" else "" end) as BASECAMP,
                   max(case when studio = "CANVAS" then "x" else "" end) as CANVAS,
                   max(case when studio = "HORIZON" then "x" else "" end) as HORIZON,
                   max(case when studio = "LAUNCHPAD" then "x" else "" end) as LAUNCHPAD,
                   max(case when studio = "NEBULA" then "x" else "" end) as NEBULA,
                   max(case when studio = "ORBIT" then "x" else "" end) as ORBIT,
                   max(case when studio = "PALETTE" then "x" else "" end) as PALETTE,
                   max(case when studio = "SANDBOX" then "x" else "" end) as SANDBOX,
                   max(case when studio = "STELLAR" then "x" else "" end) as STELLAR,
                   max(case when studio = "THE CLIMB" then "x" else "" end) as THECLIMB,
                   max(case when studio = "TOONIGAMI" then "x" else "" end) as TOONIGAMI,
                   max(case when studio = "TREEHOUSE" then "x" else "" end) as TREEHOUSE
            from process p1
            left join (
              select *
              from proc_leader
              union all
              select *
              from proc_checker
              union all
              select *
              from proc_staff    
            ) p2 on p1.projectNo = p2.projectNo
            and p1.process = p2.process
            group by p2.proc_leader
';

然后我试图打印到html表：

 $query2 = mysqli_query($conn, $sql2);

  while ($data2 = mysqli_fetch_assoc($query2)) {
    $username = $data2['username'];
    $apex = $data2['APEX'];
    $basecamp = $data2['BASECAMP'];
    $canvas = $data2['CANVAS'];
    $horizon = $data2['HORIZON'];
    $launchpad = $data2['LAUNCHPAD'];
    $nebula = $data2['NEBULA'];
    $orbit = $data2['ORBIT'];
    $palette = $data2['PALETTE'];
    $sandbox = $data2['SANDBOX'];
    $stellar = $data2['STELLAR'];
    $theclimb = $data2['THECLIMB'];
    $toonigame = $data2['TOONIGAMI'];
    $treehouse = $data2['TREEHOUSE'];   

            $header =
                '<th>Username</th>
                <th>Studio'.$apex.'</th>
                <th>Studio'.$basecamp.'</th>
                <th>Studio'.$canvas.'</th>
                <th>Studio'.$horizon.'</th>
                <th>Studio'.$launchpad.'</th>
                <th>Studio'.$nebula.'</th>
                <th>Studio'.$orbit.'</th>
                <th>Studio'.$palette.'</th>
                <th>Studio'.$sandbox.'</th>
                <th>Studio'.$stellar.'</th>
                <th>Studio'.$theclimb.'</th>
                <th>Studio'.$toonigame.'</th>
                <th>Studio'.$treehouse.'</th>';

            //body
            $body = '';
                $row = '<td>' . htmlspecialchars($username) . '</td>';
                $body .= "<tr>$row</tr>";
            echo "<thead>$header</thead><tbody>$body</tbody>";      
}

但似乎没有按照我的意愿行事。以下是我的表格现在的样子：

| username | studiox     | studiox       | studio       |
+----------+-------------+---------------+--------------+
| Aaron    |             |               |              |
| username | studio      | studio        | studiox      |
| Adel     |             |               |              |
| username | studiox     | studiox       | studio       |
| John     |             |               |              |
| username | studiox     | studiox       | studio       |
| James    |             |               |              |
| username | studio      | studio        | studiox      |
| Kate     |             |               |              |
| username | studiox     | studio        | studio       |
| Peter    |             |               |              |

问题是什么，我可以正确打印表吗？谢谢

Answer 1

如果您想保留while循环：

$query2 = mysqli_query($conn, $sql2);

$header = '<tr><th>Username</th>
            <th>Studio APEX</th>
            <th>Studio BASECAMP</th>
            <th>Studio CANVAS</th>
            <th>Studio HORIZON</th>
            <th>Studio LAUNCHPAD</th>
            <th>Studio NEBULA</th>
            <th>Studio ORBIT</th>
            <th>Studio PALETTE</th>
            <th>Studio SANDBOX</th>
            <th>Studio STELLAR</th>
            <th>Studio THECLIMB</th>
            <th>Studio TOONIGAMI</th>
            <th>Studio TREEHOUSE</th></tr>';
$body = '';
while ($data2 = mysqli_fetch_assoc($query2)) {
    $username = $data2['username'];
    $apex = $data2['APEX'];
    $basecamp = $data2['BASECAMP'];
    $canvas = $data2['CANVAS'];
    $horizon = $data2['HORIZON'];
    $launchpad = $data2['LAUNCHPAD'];
    $nebula = $data2['NEBULA'];
    $orbit = $data2['ORBIT'];
    $palette = $data2['PALETTE'];
    $sandbox = $data2['SANDBOX'];
    $stellar = $data2['STELLAR'];
    $theclimb = $data2['THECLIMB'];
    $toonigame = $data2['TOONIGAMI'];
    $treehouse = $data2['TREEHOUSE'];

    $row = '<td>' . htmlspecialchars($username) . '</td>
                <td>' . $apex . '</td>
                <td>' . $basecamp . '</td>
                <td>' . $canvas . '</td>
                <td>' . $horizon . '</td>
                <td>' . $launchpad . '</td>
                <td>' . $nebula . '</td>
                <td>' . $orbit . '</td>
                <td>' . $palette . '</td>
                <td>' . $sandbox . '</td>
                <td>' . $stellar . '</td>
                <td>' . $tdeclimb . '</td>
                <td>' . $toonigame . '</td>
                <td>' . $treehouse . '</td>';
    $body .= '<tr>' . $row . '</tr>';
}
echo '<table><thead>' . $header . '</thead><tbody>' . $body . '</tbody></table>';

请确保您没有循环错误的部分。在你的情况下，你只想在循环中构建表的主体。因此，在执行循环之前或之后构建头部，因此您只需执行一次而不是每次迭代。

Answer 2

问题是你是在循环中制作表头，所以试试这个：

[]

Answer 3

这是值得考虑的事情 - 虽然我应该强调我不是PHP编码器......

<?php

$my_array = array(
    0 => 1,
    1 => 2,
    2 => 3,
    3 => 5,
    4 => 7
);

for($i=0;$i<10;$i++){
echo $i;
if(in_array($i,$my_array)){echo " yes <br>\n";} else {echo " no <br>\n";}
}

?>

...输出

0 no
1 yes
2 yes
3 yes
4 no
5 yes
6 no
7 yes
8 no
9 no

将数据从数据库打印到html表

3 个答案: