我的数据库中有这些数据:
我尝试使用guest_identifier的最新created_at值获取foreign_ids。
在这种情况下,我希望:
foreign_id: 5 for guest_identifier: 12345
foreign_id: 5 for guest_identifier: 2345
foreign_id: 4 for guest_identifier: 345
现在我想计算这个结果并返回类似的内容:
[
{
"foreign_id": 5,
"occurrence": 2
},
{
"foreign_id": 4,
"occurrence": 1
}
]
这就是我尝试获得此结果的方法:
$qb = $this->createQueryBuilder('statistic')
->select('statistic.foreignId, COUNT(statistic.foreignId) as occurrence')
->where('statistic.guideId = :guideId')
->andWhere('statistic.type = :type')
->andWhere('statistic.createdAt BETWEEN :startDate AND :endDate')
->groupBy('statistic.guestIdentifier')
->setParameters(array(
'guideId' => $guideId,
'type' => 'answer_clicked',
'startDate' => $startDate,
'endDate' => $endDate
))
->getQuery();
$stats = $qb->getResult();
return $stats;
问题是,我的结果如下:
[
{
"foreignId": 5,
"occurrence": "3"
},
{
"foreignId": 5,
"occurrence": "3"
},
{
"foreignId": 4,
"occurrence": "2"
}
]
我无法找到,为什么对于foreign_id,为3,而不是2,为什么对于foreign_id,为什么出现为2而不是1:3。 我也不喜欢'知道如何将结果分组另一次。
答案 0 :(得分:1)
我可以用这个答案来解决我的问题:https://stackoverflow.com/a/28090544/7069057
我的功能现在看起来像这样:
$qb = $this->createQueryBuilder('statistic')
->select('statistic.foreignId, COUNT(statistic.foreignId)')
->where('statistic.guideId = :guideId')
->andWhere('statistic.type = :type')
->andWhere('statistic.createdAt BETWEEN :startDate AND :endDate')
->leftJoin('AppBundle\Entity\Statistic\Statistic', 'stat', Join::WITH,
'statistic.type = stat.type AND statistic.guestIdentifier = stat.guestIdentifier AND stat.createdAt > statistic.createdAt')
->andWhere('stat.createdAt IS NULL')
->groupBy('statistic.foreignId')
->setParameters(array(
'guideId' => $guideId,
'type' => 'answer_clicked',
'startDate' => $startDate,
'endDate' => $endDate
))
->getQuery();
$stats = $qb->getResult();
return $stats;