我有两张表如下:
| Table 1 | Table 2
| Column 1 | Column 2 | Column 1
|----------|----------|---------
|c1 |v1 | v1
|c1 |v2 | v2
|c1 |v4 | v3
|c2 |v2 | v4
|c2 |v7 | v5
|c3 |v1 | v6
|c3 |v3 | v7
|c3 |v4
|c3 |v6
我想"外连接"他们每组获得以下结果
| Column 1 | Column 2
|----------|---------
|c1 |v3
|c1 |v5
|c1 |v6
|c1 |v7
|c2 |v1
|c2 |v3
|c2 |v4
|c2 |v5
|c2 |v6
|c3 |v2
|c3 |v5
|c3 |v7
基本上查找表2中表1中与表1不匹配的每个值,在此方案中为第1列。
我最初尝试加入2个表似乎没有产生我在例如:
之后的结果SELECT * FROM
Table1 T1
FULL OUTER JOIN Table2 T2 on t1.Column2 = t2.Column1
where t1.column1 is null
答案 0 :(得分:2)
此外,您可以使用EXCEPT
:
SELECT DISTINCT t1.c1
,t2.c1
FROM @t1 t1
CROSS APPLY @t2 t2
EXCEPT
SELECT *
FROM @t1
答案 1 :(得分:1)
这应该做你需要的:
declare @t1 table(c1 nvarchar(5),c2 nvarchar(5));
declare @t2 table(c1 nvarchar(5));
insert into @t1 values ('c1','v1'),('c1','v2'),('c1','v4'),('c2','v2'),('c2','v7'),('c3','v1'),('c3','v3'),('c3','v4'),('c3','v6');
insert into @t2 values ('v1'),('v2'),('v3'),('v4'),('v5'),('v6'),('v7');
select ta.c1
,t2.c1 as c2
from @t2 t2
cross apply (select distinct c1 from @t1) ta
left join @t1 t1
on(t2.c1 = t1.c2
and ta.c1 = t1.c1
)
where t1.c1 is null
order by ta.c1
,ta.c1;
输出:
c1 c2
------
c1 v3
c1 v5
c1 v6
c1 v7
c2 v1
c2 v3
c2 v4
c2 v5
c2 v6
c3 v2
c3 v5
c3 v7
答案 2 :(得分:1)
首先生成所有组合,然后在第一个表上左联接以找出缺少的内容:
select distinct t1.c1, t2.c1
from @t1 t1
cross join @t2 t2
left join @t1 t on t1.c1 = t.c1 and t2.c1 = t.c2
where t.c1 is null