Javascript正则表达式在字符串中查找模式，排除可能的前一个单词匹配

Question

变量中有一串书写/文字：

var copypaste, replaced;
var verbdb = ["keep","know","enjoy"];
var arrayLength = verbdb.length;

for (var i = 0; i < arrayLength; i++) {
    copypaste = "One of the reasons first_name keep waking up at night, is blah blah blah. Try this, let first_name know and see blah blah blah. Remember that first_name enjoy being challenged and blah blah blah.";

    replaced = copypaste.replace(RegExp("[^let]? first_name " + verbdb[i] + "(\s|\.)","g")," first_name " + verbdb[i] + "_object_s\$1");
}

我想从replaced变量中获取的内容是，仅当first_name前面有单词let时才排除。

  

＆＃34; first_name keep_object_s在晚上醒来的原因之一，是等等等等。试试这个，让first_name知道，看看等等等等。请记住，first_name enjoy_object_s受到挑战，等等等等等等。＆＃34 ;;

所以在这个例子中：

1. 第一个模式匹配（保留）并替换为添加的_object_s，
2. 第二个模式不匹配（知道），因为单词＆＃34; let＆＃34;，所以没有替换
3. 第三种模式MATCHES（享受）并被添加的_object_s替换。

Answer 1

你可以试试这个：

(?:\b)(?!let)(?=\w+\sfirst_name\s+(know|keep|enjoy))(\w+ \w+)\s+(\w+)

Explanation

＆＃13;

＆＃13;

const regex = /(?:\b)(?!let)(?=\w+\sfirst_name\s+(know|keep|enjoy))(\w+ \w+)\s+(\w+)/g;
const str = `One of the reasons first_name keep waking up at night, is blah blah blah. Try this, let first_name know and see blah blah blah. Remember that first_name enjoy being challenged and blah blah blah`;
const subst = `$2 _object_s`;

const result = str.replace(regex, subst);
console.log(result);

＆＃13;

＆＃13;

＆＃13;