Question

我有一个popUpWindow，如果用户仍处于当前活动状态，需要在几秒钟后显示。我实现了检查活动是否未完成/销毁然后显示弹出窗口，并且它适用于周末用户:)（从活动到活动慢慢点击）但在高压测试中（活动正在重新创建，完成，快速移动形式）活动到活动）给了我那个错误：

E / UncaughtException：android.view.WindowManager $ BadTokenException：无法添加窗口 - 令牌null无效;是你的活动运行？在android.view.ViewRootImpl.setView（ViewRootImpl.java:598）在 android.view.WindowManagerGlobal.addView（WindowManagerGlobal.java:341）在android.view.WindowManagerImpl.addView（WindowManagerImpl.java:85）在android.widget.PopupWindow.invokePopup（PopupWindow.java:1279）在android.widget.PopupWindow.showAtLocation（PopupWindow.java:1040）在android.widget.PopupWindow.showAtLocation（PopupWindow.java:1003）在com.guides4art.app.ImageSlider.RatePopUp $ 3.run（RatePopUp.java:86）在android.os.Handler.handleCallback（Handler.java:743）在android.os.Handler.dispatchMessage（Handler.java:95）在android.os.Looper.loop（Looper.java:150）在android.app.ActivityThread.main（ActivityThread.java:5546） at java.lang.reflect.Method.invoke（Native Method）在 com.android.internal.os.ZygoteInit $ MethodAndArgsCaller.run（ZygoteInit.java:794）在com.android.internal.os.ZygoteInit.main（ZygoteInit.java:684）

代码：

   private void showPopUpWindow(final Activity context){


       popupWindow = new PopupWindow(context);

       LinearLayout.LayoutParams layoutParams =new LinearLayout.LayoutParams(
               LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
       popupWindow.setHeight(layoutParams.height);
       popupWindow.setWidth(layoutParams.width);
       popupWindow.setOutsideTouchable(true);
       popupWindow.setTouchable(true);
       popupWindow.setFocusable(true);
       popupWindow.setContentView(view);


       ratingBar.setOnRatingBarChangeListener(new RatingBar.OnRatingBarChangeListener() {
           @Override
           public void onRatingChanged(RatingBar ratingBar, float rating, boolean fromUser) {
               if(context instanceof CarSale) {
                   ((CarSale) context).saveRate((int) rating);
                    ((CarSale) context).initRate();
                   title.setText(""+context.getString(R.string.thanksForRate));
               }
               else
                   Log.i("kamil","error");
           }
       });
       closeButton.setOnClickListener(new View.OnClickListener() {
           @Override
           public void onClick(View v) {
               popupWindow.dismiss();
           }
       });


if(!context.isFinishing() || !context.isDestroyed() )
               activityView.post(new Runnable() {
                   @Override
                   public void run() {
                       popupWindow.showAtLocation(context.getWindow().getDecorView(), Gravity.CENTER,0,0);
                   }
               });
   }


//View Pager Class

 @Override
    public void onPageSelected(int position) {
        if(viewPager !=null){
        this.position=position;
        if(position==carList.size()-1 && isRated() && showRateBar)
            new Handler().postDelayed(new Runnable() {
                @Override
                public void run() {
                 new RatePopUp(Cars.this,activityView);
                    showRateBar=false;
                }
            },5*SECOND);

//RatePopUp constructor

 public RatePopUp(Activity context,View activityView){
        LayoutInflater inflater = (LayoutInflater) context
                .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        view = inflater.inflate(R.layout.rate_popup_layout, null);
        this.activityView=activityView;
        ratingBar = (RatingBar) view.findViewById(R.id.ratingPop);
        title= (TextView)view.findViewById(R.id.rateTitle);
        title.setText(context.getString(R.string.rate_exhibition));
        closeButton = (Button)view.findViewById(R.id.close_button);
        Typeface  typeface =Typeface.createFromAsset(context.getAssets(),"fonts/fontawesome-webfont.ttf");
        closeButton.setTypeface(typeface);
        closeButton.setText(context.getString(R.string.exitIcon));
        showPopUpWindow(context);
    }

Answer 1

试试这段代码：

 new Handler().postDelayed(new Runnable(){

    public void run() {
       popupWindow.showAtLocation(context.getWindow().getDecorView(), Gravity.CENTER,0,0);
    }

}, 200L);

而不是：

popupWindow.showAtLocation(context.getWindow().getDecorView(), Gravity.CENTER,0,0);

另外，请确保将ActivityName.this作为上下文传递..而不是getApplicationContext（）

尝试使用以下代码替换runnable中的showPopUpWindow()代码：

runOnUiThread(new Runnable() {
        @Override
        public void run() {
            if (!isFinishing()) {
                popupWindow.showAtLocation(context.getWindow().getDecorView(), Gravity.CENTER, 0, 0);
            }
        }
    });

Answer 2

在使用弹出窗口时，应该有两种状态：

Activity 是活动的，即 Activity 没有被销毁并完成

如果活动被创建或者你传递的父视图附加到窗口示例代码如下：

  val decorView = ctx.window.decorView
  decorView.post {
       val posArr = IntArray(2)
       anchorView.getLocationInWindow(posArr)
       val yOffset = posArr[1] - anchorView.height + verticalOffset
       if (isActivityAlive(ctx) && decorView.isAttachedToWindow) {
           pop.showAtLocation(decorView, Gravity.TOP, 0, yOffset)
       }
  }

  private fun isActivityAlive(ctx: Activity?): Boolean {
       return ctx != null && !ctx.isDestroyed && !ctx.isFinishing
  }

Answer 3

希望这会对你有帮助......

替换：

pwindow.showAtLocation(popupView, Gravity.CENTER, 0, 0);

使用：

new Handler().postDelayed(new Runnable(){

    public void run() {
        pwindow.showAtLocation(popupView, Gravity.CENTER, 0, 0);
    }

}, 100L);

Answer 4

在我的研究中，您无法在没有活动的情况下调用弹出窗口。弹出窗口不能在弹出窗口或对话框中调用。

BadTokenException：无法添加窗口 - 令牌null无效;你的活动在运行吗？ in activity.isFinishing statment

4 个答案: