Question

我在我的javascript中面临某种问题，我认为它正在努力打开一个小窗口，但我不知道它现在是如何工作的。这里是我的javascript代码下面我的php和html代码

<?php
require_once '../core/init.php';
$id = $_POST['id'];
if(is_numeric($id) && $id > 0 && $id == round($id, 0)){
 $id = $_POST['id'];

} else {
 exit;
}
$id = (int)$id;
$sql = "SELECT * FROM products WHERE id = '$id'";
$result = $db->query($sql);
$product = mysqli_fetch_assoc($result);
$brand_id = $product['brand'];
$sql = "SELECT brand FROM brand WHERE id = '$brand_id'";
$brand_query = $db->query($sql);
$brand = mysqli_fetch_assoc($brand_query);
$sizestring = $product['sizes'];
$size_array = explode(',', $sizestring);
?>

<!-- Details Modal -->
<?php ob_start(); ?>
<div class="modal fade details-1" id="details-modal" tabindex="-1" role="dialog" aria-labelledby="details-1" aria-hidden="true">
    <div class="modal-dialog modal-lg">
        <div class="modal-content">
        <div class="modal-header">
            <button class="close" type="button" onclick="closemodal()" aria-label="close">
                <span aria-hidden="true">&times;</span>
            </button>
            <h4 class="modal-title text-center"><?php echo $product['title']; ?></h4>
        </div>
        <div class="modal-body">
            <div class="container-fluid">
                <div class="row">
                    <div class="col-sm-6">
                        <div class="center-block">
                            <img src="<?php echo $product['image']; ?>" alt="<?php echo $product['title']; ?>" class="details img-responsive">
                        </div>
                    </div>
                    <div class="col-sm-6">
                        <h4>Details</h4>
                        <p><?php echo $product['description']; ?></p>
                        <hr>
                        <p>Price: $<?php echo $product['price']; ?></p>
                        <p>Brand: <?php echo $brand['brand']; ?></p>
                        <form action="add_cart.php" method="post">
                            <div class="form-group">
                                <div clss="col-xs-3">
                                    <label for="quantity">Quantity:</label>
                                    <input type="text" class="form-control" id="quantity" name="quantity">
                                </div>
                            </div>
                            <div class="form-group">
                                <label for="size">Size:</label>
                                <select name="size" id="size" class="form-control">
                                    <option value=""></option>
                                    <?php foreach($size_array as $string) {
                                        $string_array = explode(':', $string);
                                        $size = $string_array[0];
                                        $quantity = $string_array[1];
                                        echo '<option value="'.$size.'">'.$size.' ('.$quantity.' Available)</option>';
                                        } ?>
                                </select>
                            </div>
                        </form>
                    </div>
                </div>
            </div>
        </div>
        <div class="modal-footer">
            <button class="btn btn-default" onclick="closemodal()">Close</button>
            <button class="btn btn-warning" type="submit"><span class="glyphicon glyphicon-shopping-cart"></span>Add To Cart</button>
        </div>
        </div>
    </div>
</div>
<script>
function closemodal(){
jQuery ('#details-modal').modal('hide');
setTimeout(function(){
    jQuery('#details-modal').remove();
    jQuery('.modal-backdrop').remove();
    },500);
}
</script>
<?php echo ob_get_clean(); ?>

Answer 1

查看var_dump($product);结果后：

array(10) {
    ["id"]=> string(1) "1"
    ["title"]=> string(12) "Levi's Jeans"
    ["price"]=> string(5) "29.99"
    ["list_price"]=> string(5) "39.99"
    ["band"]=> string(1) "1"
    ["categories"]=> string(1) "6"
    ["image"]=> string(24) "images/products/men4.png"
    ["description"]=> string(16) "Description here"
    ["featured"]=> string(1) "1"
    ["sizes"]=> string(14) "28:3,32:2,36:5"
}

很明显，您没有名为＆＃39;品牌in your products`表的字段。

brand的最近字段名称是band，我认为这是一个错字。因此，如果您更改代码的这一行：

`$brand_id = $product['brand'];`

到此

`$brand_id = $product['band'];`

然后你将解决错误

注意：未定义的索引：品牌

此查询$sql = "SELECT * FROM products WHERE id = '$id'";由于$id为integer，因此无需将其括在单引号中，您可以像这样查询：

$sql = "SELECT * FROM products WHERE id = $id";

同时查看您的查询，您有两个查询，您可以使用简单的join

将它们合并到一个查询中

你有'＆＃34; SELECT * FROM产品WHERE id =＆＃39; $ id＆＃39;＆＃34;和＆＃34; SELECT品牌FROM品牌WHERE id =＆＃39; $ brand_id＆＃39;＆＃34;

在表格products中，字段band是表brand字段id的外键所以您只需编写此查询：

$sql = "SELECT products.*, brand.brand FROM products left join brand on products.band = brand.id WHERE products.id = $id";

因此，php文件顶部的detailsmodal.php部分将如下所示：

<?php
require_once '../core/init.php';
$id = $_POST['id'];
if(is_numeric($id) && $id > 0 && $id == round($id, 0)){
 $id = $_POST['id'];
} else {
 exit;
}
$id = (int)$id;

$sql = "SELECT products.*, brand.brand FROM products left join brand on products.band = brand.id WHERE products.id = $id";
$result = $db->query($sql);
$product = mysqli_fetch_assoc($result);
$sizestring = $product['sizes'];
$size_array = explode(',', $sizestring);
?>

然后只在html的这一行：

<p>Brand: <?php echo $brand['brand']; ?></p>

您必须将其更改为

<p>Brand: <?php echo $product['brand']; ?></p>

注意：由于您使用的是mysqli，因此强烈建议您使用prepared statements而不是直接将变量放入查询中

在javascript和php上有问题开放模式

1 个答案: