Question

我正在使用键盘记录器来学习pyHook，但似乎event.Ascii给了我错误的ASCII值。例如，我得到任何符号或数字0，A得1（应该是65）等等。

import pyHook, pythoncom

def OnKeyboardEvent(event):
    key = chr(event.Ascii)
    print(key)
    return 0
hm = pyHook.HookManager()
hm.KeyDown = OnKeyboardEvent
hm.HookKeyboard()
pythoncom.PumpMessages()

我找到了一种修复方法，它使用event.KeyID代替event.Ascii。但是，因为我只得到字母和数字 - 符号是完全错误的。

这是一个Python问题，还是某种键盘问题？

Answer 1

手动解析KeyID似乎是唯一的选择，这就是我的做法：

import logging
import pyHook, pythoncom

def on_keyboard_event(event):
    mappings = {None: "<backspace>", 8: "<del>", 13: "\n", 27: "<esc>", 32: " ", 46: "<del>", 91: "<win>",
                160: "<shft>", 162: "<ctr>", 164: "<alt>", 165: "<ralt>", 9: "<tab>",
                48: "0", 49: "1", 50: "2", 51: "3", 52: "4", 53: "5", 54: "6", 55: "7", 56: "8", 57: "9",
                37: "←", 38: "↑", 39: "→", 40: "↓",
                192: "ö", 222: "ä", 186: "ü", 187: "+", 191: "#",
                188: ",", 190: ".", 189: "-", 219: "ß", 221: "´",
                }

    try:
        id = event.KeyID
        char = mappings.get(id, chr(id).lower())
        if not id in mappings and char not in alpha:
            char = "<%s,%s>" % (char, str(event.KeyID))
        print(char, end="")
    except Exception as e:
        logging.exception(e)

    return True


hm = pyHook.HookManager()
hm.KeyDown = on_keyboard_event
hm.HookKeyboard()
pythoncom.PumpMessages()

这适用于德语键盘布局，因此您可能需要编辑映射。有些键仍然缺失，所以请随意扩展或改进这篇文章。

pyHook给出错误的ASCII值

1 个答案: