Mongoose - 在保存文档之前为每个对象生成ObjectID

时间:2017-01-13 00:50:17

标签: javascript node.js mongoose mongoose-schema objectid

我想为我的数组中存在的每个Object生成一个ObjectID。问题是我从其他服务器获取带有.forEach语句的产品并将其推入我的数组中而没有生成ObjectID的Schema ....

产品架构:

const productsSchema = new mongoose.Schema({

  apiKey: String,
  domain: String,
  totalcount: Number,
  totaldone: Number,
  allSKUS: Array,
  allProducts: Array,
  created_at: { type: Date },
  updated_at: { type: Date },

}, { collection: 'products', timestamps: true });

productsSchema.plugin(uniqueValidator);

const Products = mongoose.model('Products', productsSchema);

module.exports = Products;

我的代码:

const newProduct = {

  apiKey: userApiProducts.apiKey,
  domain: userApiProducts.domain,
  totalcount: userApiProducts.totalcount,
  totaldone: userApiProducts.totaldone,
  allSKUS: userApiProducts.allSKUS,
  allProducts: userApiProducts.allProducts // generate ObjectID for each object that gets pushed inside the Array
};

Products.findOneAndUpdate( userApiProducts.domain, newProduct, {upsert:true} , (err, existingProducts) => {
  if (err) { return next(err); }
});

输出:

// Please Check ADD OBJECT ID HERE comment. This is where i want to generate an unique ObjectID before I push the data. I tried with var id = mongoose.Types.ObjectId(); but i'm afraid it will not be Unique...

{
        "_id" : ObjectId("58780a2c8d94cf6a32cd7530"),
        "domain" : "http://example.com",
        "updatedAt" : ISODate("2017-01-12T23:27:15.465Z"),
        "apiKey" : "nf4fh3attn5ygkq1t",
        "totalcount" : 11,
        "totaldone" : 11,
        "allSKUS" : [
                "Primul",
                "Al doilea",
                "Al treilea"
        ],
        "allProducts" : [
            {
                // ADD OBJECT ID HERE
                "id": 1,
                "sku": "Primul",
                "name": "Primul",
                "status": 1,
                "total_images": 2,
                "media_gallery_entries": [
                    {
                        "id": 1,
                        "media_type": "image",
                        "label": null,
                        "position": 1,
                        "disabled": false,
                        "types": [
                            "image",
                            "small_image",
                            "thumbnail",
                            "swatch_image"
                        ],
                        "file": "/g/r/grafolio_angel_and_devil.png"
                    },
                    {
                        "id": 2,
                        "media_type": "image",
                        "label": null,
                        "position": 2,
                        "disabled": false,
                        "types": [],
                        "file": "/g/r/grafolio_angel_and_devil_thumbnail.jpg"
                    }
                ]
            },
            {
                // ADD OBJECT ID HERE
                "id": 3,
                "sku": "Al doilea",
                "name": "Al doilea",
                "status": 1,
                "total_images": 2,
                "media_gallery_entries": [
                    {
                        "id": 4,
                        "media_type": "image",
                        "label": null,
                        "position": 2,
                        "disabled": false,
                        "types": [],
                        "file": "/g/r/grafolio_angel_and_devil_thumbnail_1.jpg"
                    },
                    {
                        "id": 5,
                        "media_type": "image",
                        "label": null,
                        "position": 3,
                        "disabled": false,
                        "types": [],
                        "file": "/b/e/before.png"
                    }
                ]
            }, etc ......
        ],
        "__v" : 0,
        "createdAt" : ISODate("2017-01-12T22:58:52.524Z")
}

有没有办法做到这一点,而不必进行大量的数据库调用?我无法想象这样的保存

array.forEach((x)=> {
    Products.save({})
}) 

希望有人已经开始研究类似的东西并为此找到了完美的解决方案!

2 个答案:

答案 0 :(得分:2)

如果要自动添加ObjectId,则需要为其定义单独的架构,并将架构的_id选项设置为true。

执行以下操作:

  • 将您的productsSchema更改为CatalogueSchema(为了方便) 理解)。
  • 为Product定义新的ProductSchema(allProducts的元素)
  • CatalogueSchema中,将allProducts定义为[Product.schema]。这会自动添加_idObjectId)。

此外,当您将timestamps选项设置为true时,您不需要将created_atupdated_at添加为架构的一部分。

目录架构

const Product = require('Product_Schema_Module_Path'); // Edit

const CatalogueSchema = new mongoose.Schema({

    apiKey: String,
    domain: String,
    totalcount: Number,
    totaldone: Number,
    allSKUS: Array,
    allProducts: [Product.schema]   
    // Note the change here (Array -> [Product.schema]
  // Creating a separate schema ensures automatic id (ObjectId)

}, { collection: 'catalogue', timestamps: true });

CatalogueSchema.plugin(uniqueValidator);

const Catalogue = mongoose.model('Catalogue', CatalogueSchema);
module.exports = Catalogue;

产品架构新架构以确保添加ObjectId

const ProductSchema = new mongoose.Schema({

    id: Number,
    sku: String,
    name: String,
    status: Number,
    total_images: Number,
    media_gallery_entries: Array

}, { _id: true, timestamps: true });  
// _id option is true by default. You can ommit it.
// If _id is set to false, it will not add ObjectId

ProductSchema.plugin(uniqueValidator);

const Product = mongoose.model('Product', ProductSchema);
module.exports = Product;

编辑在目录中保存产品

(另请注意,您必须在CatalogueSchema模块中要求ProductSchema模块)

// Map userApiProducts.allProducts to array of Product documents
const products = userApiProducts.allProducts.map(product => {
    return new Product(product);
})

const newProduct = {
    apiKey: userApiProducts.apiKey,
    domain: userApiProducts.domain,
    totalcount: userApiProducts.totalcount,
    totaldone: userApiProducts.totaldone,
    allSKUS: userApiProducts.allSKUS,
    allProducts: products
};

Catalogue
    .findOneAndUpdate({ domain: userApiProducts.domain }, newProduct, { upsert:true } , (err, products) => {
    // Handle error
});

答案 1 :(得分:0)

要将多个文档添加到Mongo,您可以使用db.collection.insert()

在Mongoose中,您可以使用Model.insertMany()

但请记住,当你在Mongoose的其他文档中有一个文档时,它们实际上并没有像Mongo那样存储。 Mongo只存储子文档的ID而不是父文档中的内容 - 甚至不存储这些ID所属的集合的任何信息。

当您使用填充时,Mongoose实际上会在对Mongo的单独请求中从数据库中检索相关文档。因此,人口是猫鼬的概念。 Mongo只存储ID,因此您需要先创建文档,然后才能插入ID。

如果不使用Mongoose,那么你想要做的事就很容易。如果需要,您可以使用自己的ID在Mongo中的一个请求中存储多个文档,并且可以在另一个请求中存储具有这些ID数组的另一个文档。

当然,如果你这样做,你将在操作期间得到不一致的状态,因为Mongo不支持交易。