Question

我最近编写了一些应该将字符串放入框中的代码如果输入是＆＃34; hello＆＃34;，输出应如下所示：

hello
e   l
l   l
l   e
olleh

我有几乎所有的代码，我把它变成了一个盒子，除了我似乎无法使这些字母排成一行。我知道我搞砸的部分，我只是不知道如何解决它。混乱的部分是引用并被评论。这是代码，谢谢！：

int num = 0;
for (int i=1;i<=word.length();i++){
    for (int a=1;a<=word.length();a++){
        if(i>1 && i<word.length() && a>1 && a<word.length())
            System.out.print(" ");
        else
            //"System.out.print(word.charAt(num));
    }
    System.out.println("");
}

Answer 1

您可以先将String反转，然后将其存储在char[]数组中。（因为我忘了使用StringBuilder#reverse()）。

然后你可以像你一样迭代2 for个循环，顶部，底部和中间行的一些条件如下：

诀窍是使用原始字符串作为顶部和左部，而反向部分则使用右侧和底部。

另请注意，您从索引1~ word.lenght()开始，这不是您想要的，因为从索引0开始打印每个字符时不是1

public class WordSquare {

    public static void main(String[] args) {
        String word = "hello";
        int num = 0;
        char[] reverseWord = new char[word.length()];
        int counter = 0;
        for (int i = word.length() - 1; i >= 0; i--) {
            reverseWord[counter] = word.charAt(i);
            counter++;
        }

        for (int i = 0; i < word.length(); i++) {
            counter = 0;
            for (int j = 0; j < word.length(); j++) {
                if (i == 0) {
                    System.out.print(word.charAt(j));
                } else {
                    if (j == 0) {
                        System.out.print(word.charAt(i));
                    } else if (j < (word.length() - 1)) {
                        if (i < (word.length() - 1)) {
                            System.out.print(" ");
                        } else {
                            System.out.print(reverseWord[j]);
                        }
                    } else {
                        System.out.print(reverseWord[i]);
                    }
                } 
            }
            System.out.println("");
        }
    }
}

产生：

hello
e   l
l   l
l   e
olleh

Answer 2

我只是假设你必须在两个for循环中进行，所以我只是添加到循环中。

    for (int i = 0; i <= word.length() - 1; i++){
        for (int a = 0; a <= word.length() - 1; a++){
            if(i > 0 && i < word.length() - 1 && a > 0 && a < word.length() - 1) {
                System.out.print(" ");
            } else if(i == word.length() - 1) {
                System.out.print(word.charAt(word.length()-1-a));
            } else if(a != word.length() - 1) {
                System.out.print(word.charAt((a+i)%word.length()));
            } else {
                System.out.print(word.charAt((a-i)%word.length()));
            }
        }
        System.out.println("");
    }

这只是两个其他陈述中的相同内容

    for (int i = 0; i <= word.length() - 1; i++){
        for (int a = 0; a <= word.length() - 1; a++){
            if(i > 0 && i < word.length() - 1 && a > 0 && a < word.length() - 1) {
                System.out.print(" ");
            } else if (a == 0 || i == 0) {
                System.out.print(word.charAt((a+i)%word.length()));
            } else {
                System.out.print(word.charAt((2*(word.length()-1)-a-i)%word.length()));
            }
        }
        System.out.println("");
    }

Answer 3

        String word = "hello";
        System.out.println(word);
        for (int i = 1; i < word.length() - 1; i++) {
            System.out.print(word.charAt(i));
            for (int j = 0; j < word.length() - 2; j++) {
                System.out.print(" ");
            }
            System.out.println(word.charAt(word.length()-i-1));
        }
        System.out.println(new StringBuilder(word).reverse().toString());

<强>输出：

hello
e   l
l   l
l   e
olleh

Answer 4

试试这个

  public void print(String word){
    System.out.println(word);
    for (int i=1;i<word.length()-1;i++){
      System.out.print(word.charAt(i));
      for (int j=0;j<word.length()-2;j++){
        System.out.print(" ");

      }
      System.out.println(word.charAt(word.length()-i-1));
    }
    System.out.println(new StringBuilder(word).reverse().toString());
  }

有趣的家庭作业问题btw

Answer 5

试试这个，更简单的逻辑

public class SchoolAssignment
{
  // arguments are passed using the text field below this editor
  public static void main(String[] args)
  {
    String input = "hello";
    String middleSpaces  = null;

    //Determine amount of space in middle rows
    StringBuilder middleSpace = new StringBuilder();
    middleSpace.append("%"); 
    middleSpace.append(String.valueOf(input.length()-2));
    middleSpace.append("s"); 
    middleSpaces = String.format(middleSpace.toString(), " ");

    //print first line
    System.out.println(input);

    //print middle lines
    for(int i = 1; i <= input.length() - 2; i++){
        StringBuilder middleLine = new StringBuilder();
        middleLine.append(input.charAt(i));
        middleLine.append(middleSpaces); 
        middleLine.append(input.charAt(input.length() - 1 - i)); 
        System.out.println(middleLine.toString());
    }

    //print last line
    StringBuilder lastLine = new StringBuilder();
    lastLine.append(input);
    lastLine=lastLine.reverse(); 
    System.out.println(lastLine);

   }
}

在Java中缺少基于表的打印逻辑

5 个答案: