我正在实现buttonclicker的修改版本 - 多人安卓游戏的通用示例。
玩家可以选择快速游戏"其中寻找多人游戏的玩家随机匹配。我希望玩家等待30秒,如果找不到匹配的玩家,则要求玩家玩电脑。
相关代码:
<div id="grandParent">
<div id="parent">
<div class="children"></div>
<div class="children"></div>
<div class="children"></div>
</div>
</div>
<div id="reference"></div>
我认为实现这一目标的最佳方法是在30秒结束时触发 @Override
public void onActivityResult(int requestCode, int responseCode,
Intent intent) {
super.onActivityResult(requestCode, responseCode, intent);
switch (requestCode) {
...
...
case RC_WAITING_ROOM:
if (responseCode == Activity.RESULT_OK) {
startGame(true);
mSYGameOn = -1;
} else if (responseCode == GamesActivityResultCodes.RESULT_LEFT_ROOM) {
leaveRoom();
} else if (responseCode == Activity.RESULT_CANCELED) {
// The code that I want to execute
leaveRoom();
gotoMyPlayWithComputerCode()
}
break;
}
super.onActivityResult(requestCode, responseCode, intent);
}
,然后执行我的自定义代码。
快速游戏叫做:
onActivityResult
现在,QuickGame的代码如下所示。代码的 @JavascriptInterface
public void multiButtonFunction (String typeButton) {
Intent intent;
switch (typeButton) {
...
...
case "button_quick_game":
// user wants to play against a random opponent right now
startQuickGame();
break;
}
}
部分是我添加到触发Handler
的部分,它将退出快速游戏界面,然后转到我的自定义代码。:
onActivityResult
可以看出,我尝试了 void startQuickGame() {
final int MIN_OPPONENTS = 1, MAX_OPPONENTS = 1;
Bundle autoMatchCriteria = RoomConfig.createAutoMatchCriteria(MIN_OPPONENTS,
MAX_OPPONENTS, 0);
RoomConfig.Builder rtmConfigBuilder = RoomConfig.builder(this);
rtmConfigBuilder.setMessageReceivedListener(this);
rtmConfigBuilder.setRoomStatusUpdateListener(this);
rtmConfigBuilder.setAutoMatchCriteria(autoMatchCriteria);
keepScreenOn();
resetGameVars();
mSYGameOn=1;
Games.RealTimeMultiplayer.create(mGoogleApiClient, rtmConfigBuilder.build());
Handler handler = new Handler();
handler.postDelayed(new Runnable()
{
@Override
public void run() {
if (mSYGameOn>0) {
setResult(Activity.RESULT_CANCELED, getIntent());
}
}
}, 10000);
}
,但这不起作用,因为setResult
没有通过它触发。我做错了什么还是有其他方法可以做同样的事情。
任何帮助都将不胜感激。
感谢
答案 0 :(得分:0)
一个非常简单的答案。处理程序代码应为:
handler.postDelayed(new Runnable()
{
@Override
public void run() {
if (mSYGameOn>0) {
finishActivity(RC_WAITING_ROOM);
}
}
}, 30000);
这会触发onActivityResult()
并将房间视为已取消,退出等候室。
文档here