Question

我正在尝试实现fastlink 2.0并且没有从Yodlee Integration文档中获取好的信息。所以看下面的帖子。

Fastlink Landing page is not getting rendered

链接中的channelAppName是什么？

Answer 1

channelAppName是Yodlee频道的名称，您尝试在该频道上启动FL2.0。这取决于Yodlee的环境/客户。

Below is the sample HTML Form, you can replace the values here and save it as an HTML page and just open it(for testing). This should launch the FL 2.0 successfully.
 
<div class='center processText'>Processing...</div><div>
<form action='<nodeURL>' method='post' id='rsessionPost'>
RSession : <input type='text' name='rsession' placeholder='rsession' value='06142015_0:9d2817f2164ef0720282fd680c882b188b776d93e4af03155b0508a09ae8e274f0caab5d2d6819bee2ec69c85044410acb356807ba69ecd3e6e28643120dab61' id='rsession'/><br/>
FinappId : <input type='text' name='app' placeholder='FinappId' value='10003600' id='finappId'/><br/>
Redirect : <input type='text' name='redirectReq' placeholder='true/false' value='true'/><br/>
Token : <input type='text' name='token' placeholder='token' value='6ea1ef4aaa1ec923aba38b911a45cbe0019a387837b0a83738ec40a8c9a24613' id='token'/><br/>
Extra Params : <input type='text' name='extraParams' placeholer='Extra Params' value='callback=http://www.yodlee.com' id='extraParams'/><br/></form></div>
<script>document.getElementById('rsessionPost').submit();</script>
 


Node URL which needs to be used to invoke Fastlink 2.0 for this sandbox account: https://node.developer.yodlee.com/authenticate/restserver/

P

yodlee fastlink 2.0中的channelAppName

1 个答案: