我希望根据其键将数组分组到子数组中。
示例数组
10/1/2017 12:52我需要将此示例数组转换为以下格式的JSON数组：
预期输出
Array
(
[0] => Array
(
[a_id] => 1
[a_name] => A1
[b_id] => 1
[b_name] => B1
[c_id] => 1
[c_name] => C1
)
[1] => Array
(
[a_id] => 1
[a_name] => A1
[b_id] => 1
[b_name] => B1
[c_id] => 2
[c_name] => C2
)
[2] => Array
(
[a_id] => 1
[a_name] => A1
[b_id] => 2
[b_name] => B2
[c_id] => 3
[c_name] => C3
)
[3] => Array
(
[a_id] => 2
[a_name] => A2
[b_id] => 3
[b_name] => B3
[c_id] => 4
[c_name] => C4
)
)
我可以使用下面的代码按键分组。
[{
"a_id": 1,
"a_name": "A1",
"b_list": [{
"b_id": 1,
"b_name": "B1",
"c_list": [{
"c_id": 1,
"c_name": "C1"
}, {
"c_id": 2,
"c_name": "C2"
}]
}, {
"b_id": 2,
"b_name": "B2",
"c_list": [{
"c_id": 3,
"c_name": "C3"
}]
}]
}, {
"a_id": 2,
"a_name": "A2",
"b_list": [{
"b_id": 3,
"b_name": "B3",
"c_list": [{
"c_id": 4,
"c_name": "C4"
}]
}]
}]
但是我的实际情况涉及分组到子数组中没有用。
期待看看是否有优化的方法或有用的功能来进入我期望的JSON响应。
注意：我在这里研究一个通用用例。例如：$array = array(
array("a_id" => "1","a_name" => "A1","b_id" => "1","b_name" => "B1","c_id" => "1","c_name" => "C1"),
array("a_id" => "1","a_name" => "A1","b_id" => "1","b_name" => "B1","c_id" => "2","c_name" => "C2"),
array("a_id" => "1","a_name" => "A1","b_id" => "2","b_name" => "B2","c_id" => "3","c_name" => "C3"),
array("a_id" => "2","a_name" => "A2","b_id" => "3","b_name" => "B3","c_id" => "4","c_name" => "C4")
);
$return = array();
foreach($array as $val) {
$return[$val["a_id"]][] = $val;
}
print_r($return);
为国家/地区，a_list为州，b_list为城市。
答案 0 :(得分：2)
man是数组的非常具体的用例。那么这是你的解决方案。
$array = <YOUR SAMPLE ARRAY>
$output = [];
/*
* Nesting array based on a_id, b_id
*/
foreach ($array as $item) {
$aid = $item['a_id'];
$bid = $item['b_id'];
$cid = $item['c_id'];
if(!isset($output[$aid])){
$output[$aid] = [
'a_id' => $item['a_id'],
'a_name' => $item['a_name'],
'b_list' => [
$bid => [
'b_id' => $item['b_id'],
'b_name' => $item['b_name'],
'c_list' => [
$cid = [
'c_id' => $item['c_id'],
'c_name' => $item['c_name']
]
]
]
]
];
} else if (!isset($output[$aid]['b_list'][$bid])){
$output[$aid]['b_list'][$bid] = [
'b_id' => $item['b_id'],
'b_name' => $item['b_name'],
'c_list' => [
$cid => [
'c_id' => $item['c_id'],
'c_name' => $item['c_name']
]
]
];
} else if(!isset($output[$aid]['b_list'][$bid]['c_list'][$cid])) {
$output[$aid]['b_list'][$bid]['c_list'][$cid] = [
'c_id' => $item['c_id'],
'c_name' => $item['c_name']
];
} else {
// Do/Dont overrider
}
}
/*
* Removing the associativity from the b_list and c_list
*/
function indexed($input){
$output = [];
foreach ($input as $key => $item) {
if(is_array($item)){
if($key == 'b_list' || $key == 'c_list'){
$output[$key] = indexed($item);
} else {
$output[] = indexed($item);
}
} else {
$output[$key] = $item;
}
}
return $output;
}
$indexed = indexed($output);
print_r(json_encode($indexed, 128));
答案 1 :(得分：2)
那里有趣的要求。 这是我的可扩展的通用解决方案。
function transform($array, $group=[
['a_id','a_name','b_list'],
['b_id','b_name','c_list'],
['c_id','c_name'],
]){
foreach($array as $a){
$r = &$result;
foreach($group as $g){
$x = &$r[$a[$g[0]]];
$x[$g[0]] = $a[$g[0]];
$x[$g[1]] = $a[$g[1]];
if(isset($g[2])) $r = &$x[$g[2]]; else break;
}
}
return transformResult($result);
}
function transformResult($result){
foreach($result as &$a)
foreach($a as &$b)
if(is_array($b)) $b = transformResult($b);
return array_values($result);
}
要扩展此解决方案，您所要做的就是修改$group参数，
直接在函数声明中或通过传递适当的值作为第二个参数。
用法示例：
echo json_encode(transform($array), JSON_PRETTY_PRINT);
假设示例中的$array输入相同，这将返回相同的输出。
答案 2 :(得分：2)
现在，这是在给定情况下效果最佳的代码。我创建了类似的情况，然后详细解释了解决方案。
<强>场合
订单表格是多页的，具体取决于所选包裹的天数。每个包的详细信息都存储在数据库中，包含以下字段：
为了将每天的膳食选择和当天的服务作为订单存储在数据库中，我需要一个可以动态定义/填充的多维PHP数组。
预期输出类似于：
Array
(
[Day 1] => Array
(
[meal_id_1] => Unique ID //to be replaced with user selection
[meal_code_1] => Meal Name //to be replaced with user selection
[meal_type_1] => Meal //prefilled based on the selected package
[meal_id_2] => Not Available //to be replaced with user selection
[meal_code_2] => 2 //to be replaced with user selection
[meal_type_2] => Meal //prefilled based on the selected package
)
[Day 2] => Array
(
[meal_id_1] => Unique ID //to be replaced with user selection
[meal_code_1] => Meal Name //to be replaced with user selection
[meal_type_1] => Meal //prefilled based on the selected package
[meal_id_2] => Not Available //to be replaced with user selection
[meal_code_2] => 2 //to be replaced with user selection
[meal_type_2] => Meal //prefilled based on the selected package
)
以上数组是根据所解释的结构，份数和天数动态创建的。下面是代码并做了一些解释。
首先，我们必须声明两个PHP数组。
$total_meals_array = []; //Primary, Multidimension Array
$meals_selected_array = []; //Meals Details Array to be used as primary array's key value.
执行此操作后，运行MySQL查询以从数据库中读取包。现在根据结果，执行以下操作：
$total_meals_array = []; //Primary, Multidimension Array
$meals_selected_array = []; //Meals Details Array to be used as primary array's key value.
if( $num_row_packages >= 1 ) {
while($row_packages = mysqli_fetch_array ($result_packages)) {
$package_id = $row_packages['package_id'];
$package_name = $row_packages['package_name'];
$servings_count = $row_packages['servings_count'];
$days_served = $row_packages['days_served'];
//this for loop is to repeat the code inside `$days_served` number of times. This will be defining our primary and main Multidimensional Array `$total_meals_array`.
for ($y = 1; $y <= $days_served; $y++) {
//once inside the code, now is the time to define/populate our secondary array that will be used as primary array's key value. `$i`, which is the meal count of each day, will be added to the key name to make it easier to read it later. This will be repeated `$meals_count` times.
for ($i = 1; $i <= $meals_count; $i++) {
$meals_selected_array["meal_id_" . $i] = "Unique ID";
$meals_selected_array["meal_code_" . $i] = "Meal Name";
$meals_selected_array["meal_type_" . $i] = "Meal";
}
//once our secondary array, which will be used as the primary array's key value, is ready, we will start defining/populating our Primary Multidimensional Array with Keys Named based on `$days_served`.
$total_meals_array["Day " . $y] = $meals_selected_array;
}
}
}
就是这样！我们的动态多维数组已经准备就绪，可以通过以下代码查看：
print "<pre>";
print_r($total_meals_array);
print "</pre>";
谢谢大家，特别是@yarwest，我很友好地回答了我的问题。
答案 3 :(得分：1)
这是代码，您可以将它用于从a_到y_深的索引。如果你不想要它，那么innerest元素为null。在最后一个元素之前终止for循环，然后单独处理最后一个元素。您也可以对此代码进行一些改进。希望这会有所帮助。
<?php
$array = array(
array("a_id" => "1","a_name" => "A1","b_id" => "1","b_name" => "B1","c_id" => "1","c_name" => "C1"),
array("a_id" => "1","a_name" => "A1","b_id" => "1","b_name" => "B1","c_id" => "2","c_name" => "C2"),
array("a_id" => "1","a_name" => "A1","b_id" => "2","b_name" => "B2","c_id" => "3","c_name" => "C3"),
array("a_id" => "2","a_name" => "A2","b_id" => "3","b_name" => "B3","c_id" => "4","c_name" => "C4")
);
$arrays = array_map(function($v){return array_chunk($v, 2, true);}, $array);
$result = [];
foreach($arrays as $value)
{
$ref = &$result;
$len = count($value);
$index = 0;
for(; $index < $len; $index++)
{
$arr = $value[$index];
$char = key($arr)[0];
$charAdd = chr(ord($char)+1);
$key = $arr[$char.'_id'].$arr[$char.'_name'];
$listKey = $charAdd.'_list';
foreach($arr as $k => $v)
{
$ref[$key][$k] = $v;
}
$ref = &$ref[$key][$listKey];
}
}
var_dump($result);
输出：在线 live demo
ei@localhost:~$ php test.php
array(2) {
["1A1"]=>
array(3) {
["a_id"]=>
string(1) "1"
["a_name"]=>
string(2) "A1"
["b_list"]=>
array(2) {
["1B1"]=>
array(3) {
["b_id"]=>
string(1) "1"
["b_name"]=>
string(2) "B1"
["c_list"]=>
array(2) {
["1C1"]=>
array(3) {
["c_id"]=>
string(1) "1"
["c_name"]=>
string(2) "C1"
["d_list"]=>
NULL
}
["2C2"]=>
array(3) {
["c_id"]=>
string(1) "2"
["c_name"]=>
string(2) "C2"
["d_list"]=>
NULL
}
}
}
["2B2"]=>
array(3) {
["b_id"]=>
string(1) "2"
["b_name"]=>
string(2) "B2"
["c_list"]=>
array(1) {
["3C3"]=>
array(3) {
["c_id"]=>
string(1) "3"
["c_name"]=>
string(2) "C3"
["d_list"]=>
NULL
}
}
}
}
}
["2A2"]=>
array(3) {
["a_id"]=>
string(1) "2"
["a_name"]=>
string(2) "A2"
["b_list"]=>
array(1) {
["3B3"]=>
array(3) {
["b_id"]=>
string(1) "3"
["b_name"]=>
string(2) "B3"
["c_list"]=>
array(1) {
["4C4"]=>
array(3) {
["c_id"]=>
string(1) "4"
["c_name"]=>
string(2) "C4"
["d_list"]=>
&NULL
}
}
}
}
}
}
答案 4 :(得分：0)
这很有趣。据我所知，您正在尝试将平面数组转换为多维数组，以及将键转换为多维表示。
顶级差异似乎位于a_*键下划线之前的部分。
然后，对于这些键中的每一个，每隔一个*_个字母都应该引出它自己的列表。
这种递归函数可以在没有硬编码的情况下完成，可以使用任意数量的级别，字母（或其他任何内容）和正确的标识符。
它似乎准确返回您在示例中显示的json（$array是您问题中定义的数组）
$multidimension = multidimensionalify($array, ['a', 'b', 'c'], ['name']);
var_dump(json_encode($multidimension, JSON_PRETTY_PRINT));
function multidimensionalify(
array $input,
array $topLevelLetters,
array $rightHandIdentifiers,
$level = 0,
$parentId = null,
$uniqueString = 'id'
)
{
$thisDimension = [];
$thisLetter = $topLevelLetters[$level];
foreach ($input as $entry)
{
$thisId = $entry["{$thisLetter}_{$uniqueString}"];
$condition = true;
if ($parentId !== null)
{
$parentLetter = $topLevelLetters[$level - 1];
$condition = $entry["{$parentLetter}_{$uniqueString}"] === $parentId;
}
if (!isset($thisDimension[$thisId]) && $condition)
{
$thisObject = new stdClass;
$thisObject->{"{$thisLetter}_{$uniqueString}"} = $thisId;
foreach ($rightHandIdentifiers as $identifier)
{
$thisObject->{"{$thisLetter}_{$identifier}"} = $entry["{$thisLetter}_{$identifier}"];
}
if (isset($topLevelLetters[$level + 1])) {
$nextLetter = $topLevelLetters[$level + 1];
$thisObject->{"{$nextLetter}_list"} = multidimensionalify($input, $topLevelLetters, $rightHandIdentifiers, $level + 1, $thisId, $uniqueString);
}
$thisDimension[$thisId] = $thisObject;
}
}
return array_values($thisDimension);
}
答案 5 :(得分：0)
尝试此函数只需传递数组和键名进行分组，然后转换为json。
public function _group_by($array, $key) {
$return = array();
foreach ($array as $val) {
$return[$val[$key]][] = $val;
}
return $return;
}