Question

家伙不重复请致使我的json开头：

[
 {

 }
]

没有根元素。我不知道如何解析这个作为你的答案。我是php的新手。目前开发一个Android应用程序，发送一个json字符串到PHP ..我的json数据是字符串格式。我怎么能在php中解析这个字符串。我需要此字符串中的每个id和name存储在数据库中...

[
 {"name":"Abhishek Singh",
  "photo":"http:\........./diary\/photos\/student\/26.png",
  "rollno":"1",
  "id":"26"},
 {"name":"Ashutosh Tripathi",
  "photo":"http:\........./diary\/photos\/student\/34.png",
  "rollno":"2",
  "id":"34"},
 {"name":"Ayushi Srivastava",
  "photo":"http:\............./diary\/photos\/student\/42.png",
  "rollno":"3",
  "id":"42"
 }
]

Answer 1

首先你的照片值不正确它的值应该是

"photo":"http://........./diary\/photos\/student\/26.png"

或

"photo":"http:/diary\/photos\/student\/26.png"

或其他不像http:\....

的东西

如果它的值是固定的那么它的解决方案是

$json = '[{"name":"Abhishek Singh",
  "photo":"http://........./diary\/photos\/student\/26.png",
  "rollno":"1",
  "id":"26"},
 {"name":"Ashutosh Tripathi",
  "photo":"http://........./diary\/photos\/student\/34.png",
  "rollno":"2",
  "id":"34"},
 {"name":"Ayushi Srivastava",
  "photo":"http://............./diary\/photos\/student\/42.png",
  "rollno":"3",
  "id":"42"}]';

$obj = json_decode($json);
foreach ($obj as $key=>$record){
    echo $record->id;
}

Answer 2

试试这个：

$data = json_decode($json,true);//$json is your json data

foreach($data as $key=>$value){
print_r($value);// this should print each array of json
}

DEMO

Answer 3

解析

try {

   JSONArray jr = new JSONArray("string_name");
   JSONObject jb = (JSONObject)jr.getJSONObject(0);
   JSONArray st = jb.getJSONArray("key");
   for(int i=0;i<st.length();i++)
       {
      String id= st.getString(i);
      String name= st.getString(i+1);
      Log.i("..........",""+key);
      // loop and add it to array or arraylist
        }
   }catch(Exception e)
   {
        e.printStackTrace();
   }

解析并将其添加到数组后。使用相同的方法填充您的微调器。

[表示json数组节点

{表示json对象节点

Answer 4

要迭代多维数组，可以使用RecursiveArrayIterator

$jsonIterator = new RecursiveIteratorIterator(
    new RecursiveArrayIterator(json_decode($json, TRUE)),
    RecursiveIteratorIterator::SELF_FIRST);

foreach ($jsonIterator as $key => $val) {
    if(is_array($val)) {
        echo "$key:\n";
    } else {
        echo "$key => $val\n";
    }
}

输出：

John:
status => Not Active
Jennifer:
status => Active
James:
status => Active
age => 52
count => 14
progress => 29857
bad => 10

PHP json解析。不要设置复制

4 个答案: