基本上这是一个调查系统,我想从我的结果表中计算“是”和“否”
| q1 | q2 | q3 | q4 | q5 | q6 | q7 | q8 | q9 | q10 |
| Yes | Yes | No | No | No | Yes | No | Yes | Yes | No |
| No | Yes | No | Yes | Yes | Yes | No | No | Yes | No |
| Yes | Yes | No | No | No | Yes | No | Yes | Yes | No |
| No | Yes | No | Yes | Yes | Yes | No | No | Yes | No |
例如我希望我的结果是q1 = 2否' s 2是和q2 = 4是0否' s等等 之后,我希望将它显示在一个简单的表格中,但我仍然对查询一无所知
<body>
<form method="POST">
<table border="1">
<tr>
<th>Answered Yes</th>
<th>Answered No</th>
</tr>
<?php
include("testdb.php");
$result= mysqli_query($con, "SELECT * FROM results");
if($result){
?>
</table>
</form>
</body>
答案 0 :(得分:0)
SELECT SUM(q1 = 'Yes') AS q1yes
, SUM(q1 = 'No') AS q1no
, SUM(q2 = 'Yes') AS q2yes
, SUM(q2 = 'No') AS q2no
...
FROM results;
答案 1 :(得分:-1)
MySql查询
SELECT
(SELECT count(q1) FROM questions WHERE q1 = 'yes') AS q1y,
(SELECT count(q1) FROM questions WHERE q1 = 'no') AS q1n,
(SELECT count(q2) FROM questions WHERE q2 = 'yes') AS q2y,
(SELECT count(q2) FROM questions WHERE q2 = 'no') AS q2n
FROM questions
LIMIT 0,1;
并为您的代码
<body>
<form method="POST">
<table border="1">
<th>Answered Yes</th>
<th>Answered No</th>
</tr>
<?php
include("testdb.php");
$result= mysqli_query($con, "SELECT
(SELECT count(q1) FROM questions WHERE q1 = 'yes') AS q1y,
(SELECT count(q1) FROM questions WHERE q1 = 'no') AS q1n,
(SELECT count(q2) FROM questions WHERE q2 = 'yes') AS q2y,
(SELECT count(q2) FROM questions WHERE q2 = 'no') AS q2n
FROM questions
LIMIT 0,1;");
if($result){
$obj = $result->fetch_object();
echo '<tr><td>Question 1 '.$obj->q1y.'Yes</td><td>Question 1 '.$obj->q1n.'No</td></tr>';
echo '<tr><td>Question 2 '.$obj->q2y.'Yes</td><td>Question 2 '.$obj->q2n.'No</td></tr>';
?>
</table>
</body>