我想在单独的视图文件中创建bootstrap模式弹出窗口的内容,并在呈现视图之前调用与视图文件相关的相应操作方法GET Action
,并将自定义对象列表传递给通过动作方法查看。
模态:
<div class="modal fade" id="assign_device" tabindex="-1">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<h4 class="modal-title">Assign Device</h4>
</div>
<div class="modal-body">
Device list here
</div>
<div class="modal-footer">
<button type="button" class="btn btn-primary">Save</button>
<button type="button" class="btn btn-primary" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
当我点击按钮时,上面的modal
弹出窗口必须出现在当前页面中(例如index.cshtml
)。
答案 0 :(得分:2)
您可以创建一个操作方法。
public PartialViewResult GetDevice()
{
var devices= FetchDevices();
return PartialView("viewName", devices);
}
您的观点将是这样的
@model DeviceModelNamespace
<div class="modal fade" id="assign_device" tabindex="-1">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<h4 class="modal-title">Assign Device</h4>
</div>
<div class="modal-body">
foreach over devicemodel
</div>
<div class="modal-footer">
<button type="button" class="btn btn-primary">Save</button>
<button type="button" class="btn btn-primary" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
并在其他视图中调用它
@Html.Partial("viewName")
并在bootstrap模型中使用它
<script>
$("#load-partial").on('click', function () {
console.log('click');
//setup modal
$('#dynamic-modal').modal({
keyboard: false,
remote: '/controllername/partialviewname'
}).show();
});
$('#dynamic-modal').on('showen.bs.modal', function(e) {
console.log('shown');
});
</script>