Question

如何使用express和mongoose更新嵌套数组值，其中是一个多维数组，需要更新单个对象键值。这是我的数据模型

{
"_id" : ObjectId("5847b92a20352925039432de"),
"user" : {
    "email" : "email@mail.io",
    "fullName" : "Name"
}
"availabilities" : [
    [
        {
            "status" : "Close",
            "end" : "03:00",
            "start" : "00:00",
            "day" : "Sunday",
            "id" : "Sunday00:00"
        },
        {
            "status" : "Close",
            "end" : "06:00",
            "start" : "03:00",
            "day" : "Sunday",
            "id" : "Sunday03:00"
        },
        {
            "status" : "Open",
            "end" : "09:00",
            "start" : "06:00",
            "day" : "Sunday",
            "id" : "Sunday06:00"
        },
        {
            "status" : "Open",
            "end" : "12:00",
            "start" : "09:00",
            "day" : "Sunday",
            "id" : "Sunday09:00"
        },
        {
            "status" : "Open",
            "end" : "15:00",
            "start" : "12:00",
            "day" : "Sunday",
            "id" : "Sunday12:00"
        },
        {
            "status" : "Open",
            "end" : "18:00",
            "start" : "15:00",
            "day" : "Sunday",
            "id" : "Sunday15:00"
        },
        {
            "status" : "Open",
            "end" : "21:00",
            "start" : "18:00",
            "day" : "Sunday",
            "id" : "Sunday18:00"
        },
        {
            "status" : "Open",
            "end" : "24:00",
            "start" : "21:00",
            "day" : "Sunday",
            "id" : "Sunday21:00"
        }
    ],
    [
        {
            "status" : "Close",
            "end" : "03:00",
            "start" : "00:00",
            "day" : "Monday",
            "id" : "Monday00:00"
        },
        {
            "status" : "Close",
            "end" : "06:00",
            "start" : "03:00",
            "day" : "Monday",
            "id" : "Monday03:00"
        },
        {
            "status" : "Open",
            "end" : "09:00",
            "start" : "06:00",
            "day" : "Monday",
            "id" : "Monday06:00"
        },
        {
            "status" : "Open",
            "end" : "12:00",
            "start" : "09:00",
            "day" : "Monday",
            "id" : "Monday09:00"
        },
        {
            "status" : "Open",
            "end" : "15:00",
            "start" : "12:00",
            "day" : "Monday",
            "id" : "Monday12:00"
        },
        {
            "status" : "Open",
            "end" : "18:00",
            "start" : "15:00",
            "day" : "Monday",
            "id" : "Monday15:00"
        },
        {
            "status" : "Open",
            "end" : "21:00",
            "start" : "18:00",
            "day" : "Monday",
            "id" : "Monday18:00"
        },
        {
            "status" : "Open",
            "end" : "24:00",
            "start" : "21:00",
            "day" : "Monday",
            "id" : "Monday21:00"
        }
    ]
]

}

这里我想从可用性数组更改第一个索引，然后是第一个索引对象状态键值。这是：{ "status" : "Close", "end" : "03:00", "start" : "00:00", "day" : "Sunday", "id" : "Sunday00:00" }

Answer 1

您可以使用positional $ operator或索引号来定位数组条目。

db.students.update(
   { _id: 4, "grades.grade": 85 },
   { $set: { "grades.$.std" : 6 } }
)

Answer 2

yourMoongosemodel.findByIdAndUpdate(id : giveId, 
 { $push: {
         availabilities[0].status : 'open'
          }
 }, {new : true}, function(err, data){
 console.log(data);
  } )

如何在mongoose中更新嵌套数组值

2 个答案: