我正在尝试复制"正确的填充"类似于excel的函数,它填充值直到下一个值不为null / nan / empty。这"右填#34;只有当下一行中的值不为空或" nan"时才能进行练习。此外,必须为每个群体做到这一点。我有以下pandas数据帧数据集。我当前的输入表是"有"。我的输出表是"想要"。
我只是python的初学者。所以任何帮助将不胜感激。 对于那些希望通过分组操作进行此操作的人,数据如下: 表"有"如下所示,分组字段" groups":
import pandas as pd
have = pd.DataFrame({ \
"groups": pd.Series(["group1","group1","group1","group2","group2","group2"]) \
,"0": pd.Series(["abc","1","something here","abc2","1","something here"]) \
,"1": pd.Series(["","2","something here","","","something here"]) \
,"2": pd.Series(["","3","something here","","3","something here"]) \
,"3": pd.Series(["something","1","something here","something","1","something here"]) \
,"4": pd.Series(["","2","something here","","2","something here"]) \
,"5": pd.Series(["","","something here","","","something here"]) \
,"6": pd.Series(["","","something here","","","something here"]) \
,"7": pd.Series(["cdf","5","something here","mnop","5","something here"]) \
,"8": pd.Series(["","6","something here","","6","something here"]) \
,"9": pd.Series(["xyz","1","something here","xyz","1","something here"]) \
})
表"想要"使用分组字段" groups":
import pandas as pd
want = pd.DataFrame({ \
"groups": pd.Series(["group1","group1","group1","group2","group2","group2"]) \
,"0": pd.Series(["abc","1","something here","anything","1","something here"]) \
,"1": pd.Series(["abc","2","something here"," anything ","2","something here"]) \
,"2": pd.Series(["abc","3","something here"," anything ","3","something here"]) \
,"3": pd.Series(["something","1","something here","","","something here"]) \
,"4": pd.Series(["something ","2","something here","","","something here"]) \
,"5": pd.Series(["","","something here","","","something here"]) \
,"6": pd.Series(["","","something here","","","something here"]) \
,"7": pd.Series(["cdf","5","something here","mnop","5","something here"]) \
,"8": pd.Series(["cdf ","6","something here"," mnop ","6","something here"]) \
,"9": pd.Series(["xyz","1","something here","xyz","1","something here"]) \
})
我尝试使用此代码,但我仍然试图熟悉groupby
和apply
语句:
grouped=have.groupby('groups')
have.groupby('groups').apply(lambda g: have.loc[g].isnull() )
#cond = have.loc[1].isnull() | have.loc[1].ne('')
want.loc[0, cond] = want.loc[0, cond].str.strip().replace('', None)
want