我在注册表单上工作,我必须填写所有字段,EditText
输入数据应该使用json解析器进入数据库。但是我在这里遇到问题..当我尝试示例{{1它给了我红线"方法fn.gettext().toString()
必须从UI线程中调用,当前推断的线程是worker"。现在一切都很好,只有这行给了我error.i不知道这是否是正确的发送方式数据作为新手在这里。
这是我的getText()
课程:
Registration.java
这是我的用于添加数据的php文件:
public class RegistrationForm extends AppCompatActivity {
EditText fn,ln,mb,em,pw,cpw,dob,gen;
Switch sw;
RadioGroup male,feml;
Switch swth;
private ProgressDialog pDialog;
private static String url_create_book = "http://cl...com/broccoli/creatinfo.php";
// JSON Node names
private static final String TAG_SUCCESS = "success";
JSONParser jsonParser = new JSONParser();
private int serverResponseCode = 0;
Context c;
int i=0;
Button sub;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_registration_form);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
fn=(EditText)findViewById(R.id.fnm) ;
ln=(EditText)findViewById(R.id.lnm) ;
mb=(EditText)findViewById(R.id.mobile) ;
em=(EditText)findViewById(R.id.email) ;
pw=(EditText)findViewById(R.id.pass) ;
cpw=(EditText)findViewById(R.id.cpass) ;
RadioButton male=(RadioButton)findViewById(R.id.rgm) ;
RadioButton feml=(RadioButton)findViewById(R.id.rgf) ;
Switch swth=(Switch)findViewById(R.id.mySwitch) ;
getSupportActionBar().setDisplayHomeAsUpEnabled(true);
sub=(Button)findViewById(R.id.sub2);
sub.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
new CreateNewProduct().execute();
// startActivity(new Intent(RegistrationForm.this, Home.class));
}
});
}
class CreateNewProduct extends AsyncTask<String, String, String> {
/**
* Before starting background thread Show Progress Dialog
* */
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(RegistrationForm.this);
pDialog.setMessage("Creating books..");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
protected String doInBackground(String... args) {
String fname = fn.getText().toString();
String lname = ln.getText().toString();
String email = em.getText().toString();
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("First_Name", fname));
params.add(new BasicNameValuePair("Last_Name",lname));
params.add(new BasicNameValuePair("email", email));
// getting JSON Object
// Note that create product url accepts POST method
JSONObject json = jsonParser.makeHttpRequest(url_create_book,
"POST", params);
// check log cat fro response
Log.d("Create Response", json.toString());
// check for success tag
try {
int success = json.getInt(TAG_SUCCESS);
if (success == 1) {
// successfully created product
Intent i = new Intent(getApplicationContext(), Login.class);
startActivity(i);
// closing this screen
finish();
} else {
// failed to create product
}
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
/**
* After completing background task Dismiss the progress dialog
* **/
protected void onPostExecute(String file_url) {
// dismiss the dialog once done
pDialog.dismiss();
}
}
我正在尝试添加几个字段,如果这将起作用..我将添加完整的字段。
<?php
/
// array for JSON response
include ('config.php');
// check for required fields
if (isset($_POST['First_Name']) && isset($_POST['Last_Name']) && isset($_POST['email'])) {
$fname = $_POST['First_Name'];
$lname = $_POST['Last_Name'];
$email = $_POST['email'];
// mysql inserting a new row
$result = mysql_query("INSERT INTO UserInfo(First_Name, Last_Name, email) VALUES('$fname', '$lname ', '$email')");
// check if row inserted or not
if ($result) {
// successfully inserted into database
$response["success"] = 1;
$response["message"] = "Product successfully created.";
// echoing JSON response
echo json_encode($response);
} else {
// failed to insert row
$response["success"] = 0;
$response["message"] = "Oops! An error occurred.";
// echoing JSON response
echo json_encode($response);
}
} else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";
// echoing JSON response
echo json_encode($response);
}
?>
答案 0 :(得分:0)
将createNewProduct更新为:
class CreateNewProduct extends AsyncTask<String, String, String> {
private String fname;
private String lname;
private String email;
/**
* Before starting background thread Show Progress Dialog
* */
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(RegistrationForm.this);
pDialog.setMessage("Creating books..");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
fname = fn.getText().toString();
lname = ln.getText().toString();
email = em.getText().toString();
}
protected String doInBackground(String... args) {
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("First_Name", fname));
params.add(new BasicNameValuePair("Last_Name",lname));
params.add(new BasicNameValuePair("email", email));
// getting JSON Object
// Note that create product url accepts POST method
JSONObject json = jsonParser.makeHttpRequest(url_create_book,
"POST", params);
// check log cat fro response
Log.d("Create Response", json.toString());
// check for success tag
try {
int success = json.getInt(TAG_SUCCESS);
if (success == 1) {
// successfully created product
Intent i = new Intent(getApplicationContext(), Login.class);
startActivity(i);
// closing this screen
finish();
} else {
// failed to create product
}
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
/**
* After completing background task Dismiss the progress dialog
* **/
protected void onPostExecute(String file_url) {
// dismiss the dialog once done
pDialog.dismiss();
}
}
在AsyncTask中,onPreExecute和onPostExecute在主线程中运行,而doInBackground在后台线程中运行,在后台线程中您无法执行任何与ui相关的操作。
答案 1 :(得分:0)
您正在doInBackground中执行UI活动
protected String doInBackground(String... args) {
String fname = fn.getText().toString();
String lname = ln.getText().toString();
String email = em.getText().toString();
........
}
getText()应该在onPreExecute或onCreate方法中。全局定义所有上述字符串。
答案 2 :(得分:-1)
这里是这类代码的corrct php,你想从edittext中添加数据..我的错误是GET和POST METHODE ......
<?php
include ('config.php');
$fname = $_POST['First_Name'];
$lname = $_POST['Last_Name'];
$email = $_POST['email'];
$stmt = mysqli_query($conn,"INSERT INTO UserInfo(First_Name,Last_Name,email) VALUES ('$fname','$lname','$email')");
/*now only submenu items of given type will be selected*/
if ($stmt) {
// successfully inserted into database
$response["success"] = 1;
$response["message"] = "Product successfully created.";
// echoing JSON response
echo json_encode($response);
} else {
// failed to insert row
$response["success"] = 0;
$response["message"] = "Oops! An error occurred.";
// echoing JSON response
echo json_encode($response);
}/*
else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";
// echoing JSON response
echo json_encode($response);
}*/
//echo json_encode($arr);
?>