Question

我想使用Hibernate Projections属性构建如下所示的查询。有人可以检查下面。我编写了类似的java代码。

DetachedCriteria dCriteria = DetachedCriteria.forClass(FinancialYearQuater.class, "FinancialYearQuater");
        dCriteria.add(Restrictions.eq("FinancialYearQuater.finYear", year));
        dCriteria.addOrder(Order.asc("finYear"));
        dCriteria.setResultTransformer(Projections.distinct(Projections.property("id")));
        List<FinancialYearQuater> list = (List<FinancialYearQuater>) findAll(dCriteria);

这是SQL查询：

select
 distinct
        this_.FINY_NAME,
        this_.FINY_YEAR,
        this_.QTR_NAME,
        this_.QTR_NO,
        this_.QTR_PERIOD 
    from
        V_FINYR_QTR this_ 
    where
        this_.FINY_YEAR=2016
    order by
        this_.FINY_YEAR asc

Answer 1

我写了下面的代码。这是获取不同数据的正确方法吗？

DetachedCriteria dCriteria = DetachedCriteria.forClass(FinancialYearQuater.class, "FinancialYearQuater");
        dCriteria.add(Restrictions.eq("FinancialYearQuater.finYear", year));
        ProjectionList projList = Projections.projectionList();
        projList.add(Projections.property("FinancialYearQuater.finYear"), "finYear");
        projList.add(Projections.property("FinancialYearQuater.finYearName"), "finYearName");
        projList.add(Projections.property("FinancialYearQuater.qtrNo"), "qtrNo");
        projList.add(Projections.property("FinancialYearQuater.qtrPeriod"), "qtrPeriod");
        dCriteria.setProjection(Projections.distinct(projList));
        dCriteria.addOrder(Order.asc("finYear"));
        List<FinancialYearQuater> list = (List<FinancialYearQuater>) findAll(dCriteria);

如何使用Hibernate Criteria和Projections构建查询

1 个答案: