Question

我只是想动态地从数据库中获取数据，所以我使用onclick ajax方法从数据库中获取数据而不重新加载..我还想在模态CSS中显示它..

<td><a style="cursor:pointer;" data-toggle="modal" data-target="#myModal" onclick="get_report(<?php echo $det->user_id; ?>);">Today Report</a>
                            <div class="modal fade" id="myModal" role="dialog">
                                <div class="modal-dialog">
                                    <div class="modal-content">
                                        <div class="modal-header">
                                            <button type="button" class="close" data-dismiss="modal">&times;</button>
                                            <h4 class="modal-title">Today Report</h4>
                                        </div>
                                        <div class="modal-body">
                                            <div id="rep_id"></div>
                                        </div>
                                        <div class="modal-footer">
                                            <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
                                        </div>
                                    </div>
                                </div>
                            </div>
                        </td>

在底部，

function get_report(sales_id)
{ 
    $.ajax({
            url: "<?php echo base_url()."Sales_exec/get_report/"; ?>",
            method: "post",
            data : { sales_id : sales_id }
        }).done(function(response){ 
               $('.modal-body').html(response);
        }); 
}
</script>

在我的控制器中，

public function get_report()
{
    $sales_id = $this->input->post('sales_id'); 
    $response = $this->Sales_exec_model->today_sales_report($sales_id);
}

我的模特是，

public function today_sales_report($id)
    {
        $query = $this->db->query('SELECT * FROM tbl_reports WHERE sales_id="'.$id.'" AND DATE(created) = CURDATE()');
        if ($query->num_rows() == 1)
        {
            $report['rep']= $query->row();
            print_r($report);die;
        }
    }

我正在模态体中输出：

数组（[rep] =＆gt; stdClass对象（[rep_id] =＆gt; 3 [client_name] =＆gt; joyner [地址] =＆gt; client_address [area] =＆gt; client_area [sales_id] =＆gt; 1 [sales_head_id] =＆gt; 85 [评论] =＆gt; 0 [pay_by] =＆gt;现金[amt_value] =＆gt; 1.00 [created] =＆gt; 2016-12-22））

有人可以帮助我将这些数据与数组分开来显示它吗？

Answer 1

将模态$ report ['rep']更改为$ report。因为您正在$ report ['rep']保存值并尝试从$ report获取值。你的模态改变了将您的$ report ['rep']更改为$ report，这将解决您的问题。

如何在php codeigniter中使用ajax从数据库中获取数据并以模态显示？

1 个答案: