大家好,我有一个问题,我不知道一会儿。我有一个从数据库返回值的循环,我希望每个值在JavaScript的onmouseover属性上查看它们的值。但它只显示所有标签的第一行值。这是代码的php部分
$result = "<table id='displayDiv' width='1000' class='table_info table-bordered table-striped table-hover'>
<tr>
<td colspan='6' class='plate'>Follow-Up Events</td>
</tr>
<tr style='text-align:center; color:#FFF; background: #31B0D5;'>
<td>Customer</td>
<td>Plate</td>
<td class='col-md-4'>Problem</td>
<td>Date Created</td>
<td></td>
</tr>";
foreach ($followArray as $customer) {
$result = $result .
"<tr style='text-align:center; background: #FFF; color:#105a99; font-weight:bold;'>
<td>$customer->company</td>
<td id='plate' onmouseover='plate();' onmouseout='plateout();'>$customer->plate</td>
<td>$customer->problem</td>
<td>$customer->date</td>
</tr>";
}
$result = $result . "</table><div id'white'></div>";
和javascript
function plate() {
document.getElementById("white").innerHTML = $("#plate").text();
}
function plateout() {
document.getElementById("white").innerHTML = "";
}
感谢您的帮助。
答案 0 :(得分:1)
当您使用原生js时,只需将this
传递到您的版功能中并使用this.innerHTML
。
同样修复html - ids应该是唯一的,所以要么将它改为一个类,要么在末尾附加一个唯一的数字(在下面的例子中我将它改为一个类) - 你永远不应该在一个循环中有一个id (除非你附加索引或类似的东西)。
白色div中应该有一个=
function plate(columnCell) {
document.getElementById('white').innerHTML = columnCell.innerHTML;
}
function plateout() {
document.getElementById('white').innerHTML = '';
}
<table id='displayDiv' width='1000' class='table_info table-bordered table-striped table-hover'>
<tr>
<td colspan='6' class='plate'>Follow-Up Events</td>
</tr>
<tr style='text-align:center; color:#FFF; background: #31B0D5;'>
<td>Customer</td>
<td>Plate</td>
<td class='col-md-4'>Problem</td>
<td>Date Created</td>
<td></td>
</tr>
<tr style='text-align:center; background: #FFF; color:#105a99; font-weight:bold;'>
<td>$customer->company</td>
<td class='plate' onmouseover='plate(this);' onmouseout='plateout(this);'>$customer->plate</td>
<td>$customer->problem</td>
<td>$customer->date</td>
</tr>
<tr style='text-align:center; background: #FFF; color:#105a99; font-weight:bold;'>
<td>$customer->company</td>
<td class='plate' onmouseover='plate(this);' onmouseout='plateout();'>$customer->plate1</td>
<td>$customer->problem</td>
<td>$customer->date</td>
</tr>
<tr style='text-align:center; background: #FFF; color:#105a99; font-weight:bold;'>
<td>$customer->company</td>
<td class='plate' onmouseover='plate(this);' onmouseout='plateout(this);'>$customer->plate2</td>
<td>$customer->problem</td>
<td>$customer->date</td>
</tr>
</table>
<div id="white"></div>
如果你想要一个jQuery解决方案然后使用新的版本(并从html中删除onmouseover和onmouseout),你可以这样做:
// run in your document ready
var white = $('#white');
$('.plate').hover(
function() {
// mouseover
white.text($(this).text());
}, function() {
// mouseoout
white.text('');
}
);