你好我是Android工作室的新手,试图让一个按钮在一个片段中工作,但它不起作用吗?
My Fragment代码:
package layout;
import android.content.Context;
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;
import android.support.design.widget.Snackbar;
import android.support.v4.app.Fragment;
import android.support.v4.widget.SearchViewCompat;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.Button;
import com.marcphi.csgoskin.R;
import com.marcphi.csgoskin.SkinListActivity;
public class NewsFragment extends Fragment implements View.OnClickListener {
View view;
Button btn;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_news, container, false);
btn = (Button) view.findViewById(R.id.button1);
btn.setOnClickListener(this);
return view;
}
public void onClick(View view){
Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG)
.setAction("Action", null).show();
Intent intent = new Intent(getActivity(), SkinListActivity.class);
startActivity(intent);
}
}
现在调试时出现错误。
答案 0 :(得分:0)
一种方法:
btn = (Button) view.findViewById(R.id.button1);
btn.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// Perform action on click
Snackbar.make(v,
"Replace with your own action",
Snackbar.LENGTH_LONG)
.setAction("Action", null).show();
Intent intent = new Intent(getActivity(),
SkinListActivity.class);
startActivity(intent);
}
});
答案 1 :(得分:0)
在onClick方法中添加:
If (view.getId() == R.id.button1) {
// Here place code of onClick method
}
答案 2 :(得分:0)
它不起作用,因为Snackbar.make()
将coordinatorLayout作为第一个参数,并且您在其中传递按钮。
如果你想使用Snackbar,你必须在你的片段中使用CoordinatorLayout作为你的rootView,然后将它传递给Snackbar,如下所示:
Snackbar.make(coordinatorLayout, "Replace with your own action", Snackbar.LENGTH_LONG)
.setAction("Action", null).show();