Question

以下是我的输入和输出.txt文件。

我希望按StatusDate和Method对数据进行分组。然后根据StatusDate和Method汇总值。

INPUT.TXT

No,Date,MethodStatus,Key,StatusDate,Hit,CallType,Method,LastMethodType
112,12/15/16,Suceess,Geo,12/15/16,1,Static,GET,12/15/16
113,12/18/16,Suceess,Geo,12/18/16,1,Static,GET,12/18/16
114,12/19/16,AUTHORIZED,Geo,12/19/16,1,Static,GET,12/19/16
115,12/19/16,AUTHORIZED,Geo,12/19/16,1,Static,GET,12/19/16
116,12/19/16,Suceess,Geo,12/19/16,1,Static,PUT,12/19/16
117,12/19/16,Suceess,Geo,12/19/16,1,Static,PUT,12/19/16
118,12/19/16,Waiting,Geo,12/19/16,1,Static,GET,12/19/16
119,12/19/16,AUTHORIZED,Geo,12/19/16,1,Static,GET,12/19/16
120,12/17/16,Suceess,Geo,12/17/16,1,Static,GET,12/17/16
121,12/17/16,Suceess,Geo,12/17/16,1,Static,GET,12/17/16
130,12/16/16,Suceess,Geo,12/16/16,1,Static,GET,12/16/16

Out.txt

StatusDate,12/15/16,12/16/16,12/17/16,12/17/16,12/18/16,12/19/16,12/19/16,12/19/16,12/19/16,12/19/16,12/19/16,Grand Total
GET,1,1,1,1,1,1,1,1,1,,,9
PUT,,,,,,,,,,1,1,2
Grand Total,1,1,1,1,1,1,1,1,1,1,1,11

我正在使用awk并将数据拆分为awk -F, '{if($8=="GET") print }'，然后计算总和值。由于文件很大，所以会有延迟。

是否有可能一步到位？那么文件操作会减少吗？

Answer 1

awk -F ',' '
   /GET/{ Get[ $2]++}
   /PUT}{ Put[ $2]++}
   {Total[$2]++}

   END {
     printf( "StatusDate')
     for (d in Total) printf( ",%s", d)
     printf( "\nTotal GET")
     for (d in Total) printf( ",%d", Get[d])
     printf( " PUT")
     for (d in Total) printf( ",%d", Put[d])
     printf( " Grand Total")
     for (d in Total) printf( ",%d", Total[d])
     printf( "\n")
     }
   ' Input.txt

将数据存储在每行的3个数组中
在最后显示结果的几个循环

Answer 2

您可以使用关联数组来跟踪聚合。

    var $scrollerOuter  = $( '.mCustomScrollbar' );
    var $dragger        = $scrollerOuter.find( '.mCSB_dragger' );
    var scrollHeight    = $scrollerOuter.find( '.mCSB_container' ).height();
    var draggerTop      = $dragger.position().top;

    var scrollTop = draggerTop / ($scrollerOuter.height() - $dragger.height()) * (scrollHeight - $scrollerOuter.height());

Answer 3

$ awk -F, 'NR==1 {printf "%s",$8$2; t="Total"; v[t]; next} 
                 {d[$2]; v[$8]; a[$2,$8]++; a[$2,t]++} 
           END   {n=asorti(d,ds); 
                  for(i=1;i<=n;i++) printf "%s", FS ds[i]; 
                  print ""; 
                  for(k in v) 
                    {printf "%s", k; 
                     for(i=1;i<=n;i++) printf "%s", FS a[ds[i],k]; 
                     print ""}}' file


MethodDate,12/15/16,12/16/16,12/17/16,12/18/16,12/19/16
PUT,,,,,2
GET,1,1,2,1,4
Total,1,1,2,1,6

如何按列值分组到行和列标题中，然后对值求和

3 个答案: