Question

我正在做一个好友列表，但效果并不好。好吧，我试图向所有用户的朋友展示但它不起作用，它只显示一个而不是全部。

在MySQL的friends_request表中我有这样的东西：

（我不知道如何在这里放置一个可绘制的表，所以我把表格的html ）

<table border="1">
    <tr>
        <td>id</td>
        <td>from_username</td>
        <td>to_username</td>
        <td>requested</td>
        <td>accepted</td>
    </tr>
    <tr>
        <td>1</td>
        <td>username1</td>
        <td>username2</td>
        <td>0</td>
        <td>1</td>
    </tr>
    <tr>
        <td>2</td>
        <td>username1</td>
        <td>username3</td>
        <td>0</td>
        <td>1</td>
    </tr>
    <tr>
        <td>3</td>
        <td>username2</td>
        <td>username3</td>
        <td>0</td>
        <td>1</td>
    </tr>
</table>

它显示的只是一个用户名而不是用户名是用户登录的所有用户...例如，在'username1'中只显示为'username2'的朋友，而不是'username3'显示我希望知道原因。

<?php
$selfriends = "SELECT * FROM friends_request WHERE from_username = '$user' OR to_username='$user' AND accepted = '1'";
$resultfriend = $sql->query($selfriends);   // select the table of friends_request from database
$rowfriend = mysqli_fetch_assoc($resultfriend); // calls the string, char or number from friends_request table

$t1 = $rowfriend['from_username']; // calls user from_username from friends_request table
$t2 = $rowfriend['to_username']; // calls user to_username from friends_request table
$accepted = $rowfriend['accepted']; // calls accepted from friends_request table
$fid = $rowfriend['id'];

/* CHECK IF FRIEND GOT SOME PICTURE */
$selPicturePro = "SELECT * FROM users WHERE username = '$t1'";
$resultsPicPro = $sql->query($selPicturePro); // select the users table and find out the content of pic
$rowProfiles = mysqli_fetch_assoc($resultsPicPro); // calls the row of profile picture.

if($rowProfiles > 1) {
    $profileView = "<img src='".$rowProfiles['profile']."' width='auto' height='155px' />";
} else {
    $profileView = "<img src='images/no-picture.png' width='auto' height='100px' />";
}

$selPicturePro2 = "SELECT * FROM users WHERE username = '$t2'";
$resultsPicPro2 = $sql->query($selPicturePro2); // select the users table and find out the content of pic
$rowProfiles2 = mysqli_fetch_assoc($resultsPicPro2); // calls the row of profile picture.

if($rowProfiles2 > 1) {
    $profileView2 = "<img src='".$rowProfiles2['profile']."' width='auto' height='155px' />";
} else {
    $profileView2 = "<img src='images/no-picture.png' width='auto' height='100px' />";
}

if($user != $t1) { // if the user is not the sender and accepted = 1, then the 
    // receiver sees the other user.
    echo '<h3>Friends</h3>';
    echo '<a href="profile.php?u='.$t1.'" class="no-style">';
    echo $profileView;.'<br />'.$t1;
    echo '</a>';
}
else if($user != $t2) { // if the user is not the receiver and accepted = 1, then the    
    // sender see the other user.
    echo '<h3>Friends</h3>';
    echo '<a href="profile.php?u='.$t2.'" class="no-style">';
    echo $profileView2.'<br />'.$t2;
    echo '</a>';
}

if($user != $t1 && $accepted == 0) {
    echo "<br clear='all' />";
    echo "<h3>Friends</h3>";
    echo "You don't have friends yet.";
}

if($user != $t2 && $accepted == 0) {
    echo "<br clear='all' />";
    echo "<h3>Friends</h3>";
    echo "You don't have friends yet.";
}           
?>

Answer 1

你需要一个循环来处理所有的朋友。此外，您可以将所有查询与联接组合在一起。

您可以更改查询，将其同时放入包含from_username的单个列，而不是复制to_username和UNION的所有代码。

在处理行时无法完成用户是否有朋友的测试，因为当您没有任何朋友时，将不会选择任何行。在循环之前执行此操作，方法是检查返回的行数。

<?php

$selfriends = "SELECT fr.username, u.profile
               FROM (SELECT from_username AS username
                     FROM friends_request
                     WHERE to_username = '$user' AND accepted = 1
                     UNION ALL
                     SELECT to_username AS username
                     FROM friends_request
                     WHERE from_username = '$user' AND accepted = 1) AS fr
               JOIN users AS u ON u.username = fr.username";
$resultfriend = $sql->query($selfriends);                                       // select the table of friends_request from database
if ($resultfriend->num_rows == 0) {
    echo "<br clear='all' />";
    echo "<h3>Friends</h3>";
    echo "You don't have friends yet.";
} else {
    echo '<h3>Friends</h3>';
    while ($rowfriend = mysqli_fetch_assoc($resultfriend)) {                        // calls the string, char or number from friends_request table
        $t1 = $rowfriend['username'];
        $profile = $rowfriend['profile'];

        if(!empty($profile)) {
            $profileView = "<img src='".$profile."' width='auto' height='155px' />";
        } else {
            $profileView = "<img src='images/no-picture.png' width='auto' height='100px' />";
        }

        <a href="profile.php?u=<?php echo $t1; ?>" class="no-style">
        <?php echo $profileView; ?><br />
        <?php echo $t1; ?>
        </a>
        <?php
    }
}

朋友列表不显示所有用户朋友

1 个答案: