我需要修改程序' x'因此它输出原始网格,但每个行和列都标有它的相应数字。即,第1列具有第一列,第1行具有第一列。我已经弄清楚如何在行前放置编号,但无法弄清楚如何修改程序以便列编号。
' X'
import random
aGrid = []
SIZE = 10
for r in range (0,SIZE,1):
aGrid.append ([])
for c in range (0,SIZE,1):
element = random.randint(0,9)
aGrid[r].append (element)
for r in range (0,SIZE,1):
for c in range (0,SIZE,1):
print(aGrid[r][c], end="")
print()
这是我尝试在行前面编号
import random
aGrid = []
SIZE = 11
for r in range (0,SIZE - 1,1):
aGrid.append ([])
aGrid[r].append (r )
aGrid[r].append (" ")
for c in range (0,SIZE + 1,1):
element = random.randint(0,9)
aGrid[r].append (element)
for r in range (0,SIZE - 1,1):
for c in range (0,SIZE + 1,1):
print(aGrid[r][c], end="")
print()
答案 0 :(得分:0)
您不需要更改aGrid
。只需打印打印循环中的行号和列号:
import random
aGrid = []
SIZE = 10
for r in range (SIZE):
aGrid.append ([])
for c in range (SIZE):
element = random.randint(0,9)
aGrid[r].append (element)
print(" ", end="")
for c in range (SIZE):
print(c, end="")
print()
for i, r in enumerate(range(SIZE)):
print(i, end="")
for c in range(SIZE):
print(aGrid[r][c], end="")
print()
输出:
0123456789
01958724133
17006217440
21488953544
35615572045
49849348546
54207744418
63316678723
76651582077
85713263320
91939404287
从1开始计数的版本,并且有一些空间以提高可读性:
import random
aGrid = []
SIZE = 10
for r in range (SIZE):
aGrid.append ([])
for c in range (SIZE):
element = random.randint(0,9)
aGrid[r].append (element)
print(" ", end=" ")
for c in range (1, SIZE + 1):
print(c, end=" ")
print()
for i, r in enumerate(range(SIZE), 1):
print('{:2d}'.format(i), end=" ")
for c in range(SIZE):
print(aGrid[r][c], end=" ")
print()
输出:
1 2 3 4 5 6 7 8 9 10
1 3 0 4 6 3 9 3 3 6 3
2 5 6 1 6 6 3 2 5 6 1
3 6 9 0 5 0 7 1 1 7 7
4 7 4 3 9 0 9 1 0 7 8
5 5 1 1 1 1 7 1 4 4 8
6 4 5 8 1 6 3 6 2 8 6
7 4 1 0 5 7 4 5 6 6 4
8 4 5 5 4 3 3 0 9 2 1
9 3 6 7 0 0 9 5 8 5 9
10 3 1 2 3 5 0 1 6 2 9