我已经问过如何在熊猫中解决它的问题。但现在我需要一个非熊猫版本。
我的代码
import glob
import os
## path
path = r'C:/x/x/Desktop/xxx/'
all_files = glob.glob(os.path.join(path, '*.csv'))
## column
column_headers = ['Date', 'Time', 'Duration', 'IP', 'Request']
## open only one csv. -- I want to read here not only 1 file --
## my approach:
## with open(all_files) as log, ....
with open('log.csv') as log, open('out355.csv', 'w') as out:
out.write(';'.join(column_headers)+'\n')
while True:
try:
lines = [next(log).strip('\n').split(' ',4) for i in range(6)][3:]
out.write(';'.join(lines[1][:2]+[l[4] for l in lines])+'\n')
except StopIteration:
break
因为我是python的新手,所以我不能仅仅修改我的运行代码。如果我能得到完整的代码,我会很高兴。
谢谢!
答案 0 :(得分:0)
您已关闭,您需要阅读每个*.csv
文件并将它们连接起来。因此,您必须打开一个新文件并使用glob读取每个csv文件。确保在执行此操作时,在其末尾的每个csv文件中都有一个尾随的新行,或者您最后得到file_x
的最后一行和{{1的第一行数据行在同一行
file_x+1
运行时:
a.csv
from glob import glob
with open('combined.csv', 'a') as combinedFile:
combinedFile.write('a,b,c,d,e\n') # Headers
for eachFile in glob('*.csv'):
if eachFile == 'combined.csv':
pass
else:
count = 0
for line in open(eachFile, 'r'):
if count != 0: # So that you don't read 1st line of every file if it contains the headers.
combinedFile.write(line)
count = 1
b.csv
a,b,c,d,e
1,2,3,4,5
6,7,8,9,10
combined.csv
a,b,c,d,e
11,12,13,14,15
16,17,18,19,20
答案 1 :(得分:-1)
这些方面应该有效:
with open('out355.csv', 'w') as out:
for csvfile in all_files:
with open(csvfile) as log:
out.write(...)
.. the rest of your script ..
答案 2 :(得分:-1)
这应该可行
import glob
import os
## path
path = r'C:/x/x/Desktop/xxx/'
all_files = glob.glob(os.path.join(path, '*.csv'))
## column
column_headers = ['Date', 'Time', 'Duration', 'IP', 'Request']
out = open('out355.csv', 'w')
out.write(';'.join(column_headers)+'\n')
for file_ in all_files:
log = open(file_)
while True:
try:
lines = [next(log).strip('\n').split(' ',4) for i in range(6)][3:]
out.write(';'.join(lines[1][:2]+[l[4] for l in lines])+'\n')
except StopIteration:
break