我正在尝试从laravel上的数据库显示数据,但是在视图刀片中不显示任何内容。每个小组都有很多lapangan(英国:法院)数据
$groups_resource = Groups::all();
$groups = [];
foreach($groups_resource as $group)
{
$g = new Groups();
$g->id_group = "Group_".$group['id_group'];
$g->name = $group['nama'];
$g->expanded = true;
$g->eventHeight = 25;
$g->children = array();
$groups[] = $g;
$lapangan_resource = Lapangan::with('groups')->orderBy('nama')->get();
foreach($lapangan_resource as $lapangan)
{
$l = new Lapangan();
$l->id_lapangan = $lapangan['id_lapangan'];
$l->name = $lapangan['nama_lapangan'];
$g->children[] = $l;
}
}
return json_encode($groups);
输出
[{"id_group":"Group_1","name":"Lapangan Badminton","expanded":true,"eventHeight":25,"children":[]},{"id_group":"Group_2","name":"Lapangan Tenis","expanded":true,"eventHeight":25,"children":[]}]
每个id_group都没有子输出 我想要什么
{"id":"group_1","name":"Indoor","expanded":true,"eventHeight":25,"children":[
{"id":"1","name":"Court 1"},
{"id":"2","name":"Court 2"},
{"id":"3","name":"Court 3"},
{"id":"4","name":"Court 4"}]},
{"id":"group_2","name":"Outdoor","expanded":true,"eventHeight":25,"children":[
{"id":"11","name":"Court 5"},
{"id":"12","name":"Court 6"},
{"id":"13","name":"Court 7"},
{"id":"14","name":"Court 8"}]}
]
有什么想法吗?
答案 0 :(得分:0)
如果要以JSON格式返回响应,则可以使用json()
方法:
return response()->json($datagrup);
OR
要将模型转换为JSON
,您应该使用toJson
方法。与toArray
类似,toJson
方法是递归的,因此所有属性和关系都将转换为JSON:
$user = App\User::find(1);
return $user->toJson();
答案 1 :(得分:0)
尽管如此,您的代码似乎已经解决了......我仍然觉得以下代码对您有用:)
我不确定$datagroup[] = $dataresource
到底是什么意思?是否要添加datagroup to dataresource
或dataresource to datagroup
...您的代码会显示某些内容,所需的输出是其他内容。
$datagroup = array_map(function($groups) use ($scheduler_resources) {
return [
'id' => $group['id_group'],
'name' => $group['nama'],
'expanded' => true,
'children' => $scheduler_resources->map(function($resource) {
return [
'id' => $resource->id_lapangan,
'name' => $resource->nama_lapangan,
];
}),
'eventHeight' => 25
];
}, $scheduler_groups);
echo json_encode($datagroup);
// or
// return response()->json($datagroup);
注意: - 请确保每个$scheduler_resources
$datagroup
不同