我试图以下列方式提取文字:
$subname = "subarray({value=subarray({0.5, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48}, EXCEL*48, 1)";
preg_match('#\{(.*?)\}#',$subname, $match, PREG_OFFSET_CAPTURE);
print_r($match[1][1]);
$matchs = substr( $subname, 0, $match[1][1]);
print_r($matchs);
我想从$ subname
获取以下文字我正在努力争取第二位(获得EXCEL字样)。我想知道是否有可能让preg_match给我剩下的字符串?
答案 0 :(得分:1)
您可以使用
'#\{([\s\d.,]*)},\s*(\p{L}+)(\*\d+)#'
请参阅regex demo。
详细:
\{
- {
([\s\d.,]*)
- 第1组捕获0 +空格,数字,逗号和点}
- 文字}
,
- 逗号\s*
- 0+ whitespaces (\p{L}+)
- 第2组:一个或多个字母(\*\d+)
- 第3组:*
和1+位数。请参阅下面的PHP demo。
$subname = "subarray({value=subarray({0.5, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48}, EXCEL*48, 1)";
$res = array();
if (preg_match('#\{([\s\d.,]*)},\s*(\p{L}+)(\*\d+)#',$subname, $match)) {
$res = explode(", ", $match[1]);
array_push($res, $match[2]);
array_push($res, $match[3]);
}
print_r($res);