您好我试图使用此端点www.reddit.com/reddits.json在Android上显示一些列表,我收到此错误,下面是我的代码。
我的主要活动类上有这个asynctask类:
private class AsyncListLoader extends AsyncTask<String, Integer, JSONObject>{
private JSONParser jsonParser = new JSONParser();
private static final String REDEEM_URL = "http://www.reddit.com/reddits.json";
private HashMap<String, String> param = new HashMap<>();
@Override
protected JSONObject doInBackground(String... params) {
JSONObject json = jsonParser.makeHttpRequest(REDEEM_URL, "GET", param);
if (json != null) {
Log.d("JSON result", json.toString());
return json;
}
else {
Log.d("JSON result", "is null");
}
return null;
}
@Override
protected void onPostExecute(JSONObject s) {
try {
if(!s.has("kind")){
Toast.makeText(MainActivity.this, "Something went wrong", Toast.LENGTH_LONG).show();
}
else {
JSONObject list = s.getJSONObject("data");
JSONArray childrens = list.getJSONArray("children");
for(int i = 0; i < childrens.length(); i++){
JSONObject o = childrens.getJSONObject(i).getJSONObject("data");
Feed f = new Feed(o.getString("icon_img"),o.getString("banner_img"),o.getString("display_name"));
MainActivity.this.adapter.add(f);
}
}
} catch (JSONException e){
e.printStackTrace();
}
}
}
获取时makehttpRequest:
if(method.equals("GET")){
// request method is GET
if (sbParams.length() != 0) {
url += "?" + sbParams.toString();
}
try {
urlObj = new URL(url);
conn = (HttpURLConnection) urlObj.openConnection();
conn.setDoOutput(false);
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept-Charset", charset);
conn.setConnectTimeout(15000);
conn.connect();
} catch (IOException e) {
e.printStackTrace();
}
}
try {
//Receive the response from the server
InputStream in = new BufferedInputStream(conn.getInputStream());
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
result = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
Log.d("JSON Parser", "result: " + result.toString());
} catch (IOException e) {
e.printStackTrace();
}
conn.disconnect();
// try parse the string to a JSON object
try {
jObj = new JSONObject(result.toString());
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON Object
return jObj;
我在网上测试了另外一个json端点并且它们正在工作。我不知道为什么会这样。
编辑: