Django：没有反向比赛

Question

def test_post_request_for_api_view(self):
    data = {
        "email": self.user.email,
    }
    url = self.reverse('users:the_api', self.user.pk)
    response = self.json_post(data, url=url)

    self.mock.assert_called_once_with(self.user)
    data2 = json.loads(response.content.decode('utf-8'))
    self.assertEqual(data2, {
        'booking_order': ['ABCDEFGHIJKL'],
        'transaction_total': '20000.00'
    })

urls.py

urlpatterns = [
url(
    regex=r'^$',
    view=views.UserListView.as_view(),
    name='list'
),
url(
    regex=r'^~redirect/$',
    view=views.UserRedirectView.as_view(),
    name='redirect'
),
url(
    regex=r'^(?P<username>[\w.@+-]+)/$',
    view=views.UserDetailView.as_view(),
    name='detail'
),
url(
    regex=r'^~update/$',
    view=views.UserUpdateView.as_view(),
    name='update'
)    ,
url(
    regex=r'^the_api/$',
    view =  views.UserApiView.as_view(),
    name='the_api'
),

views.py

class UserApiView(APIView):
    authentication_classes = authentication.TokenAuthentication ###Am assuming you're authenticating via a token

    def get(self, request):
        """
        Get user based on username.
        Am getting only the username since that's the only field used above.
        :param request:
        :param format:
        :return:
        """
        details = User.objects.all()
        serializer = UserSerializer(details, many=True)
        return Response(serializer.data  )

    def post(self, request, format=None):
        """
        Create a new user instance
        :param request:
        :param format:
        :return:
        """
        serializer = UserSerializer(request.data)
        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data)
        return Response(serializer.errors)

尽管我理解Django中的反向是如何工作的，但我相信上面的测试通过，我只需要在我的中有一个 the_api 网址urls.py 。 然而，即使这样，测试也没有通过。 因此，我很想知道正确的做法是什么。 我如何让测试运行？

我不断得到的错误是：

  

django.urls.exceptions.NoReverseMatch：反向＆＃39; the_api＆＃39;参数＆＃39;（1，）＆＃39;和关键字参数＆＃39; {}＆＃39;未找到。尝试了1种模式：[＆＃39;用户：the_api / $＆＃39;]

Answer 1

你在网址上接受了争论吗？查看代码，您应该在urls.py文件中输入以下内容：

url(r'the_api/(\d+)/$', your_view, name="the_api")

可能您应该粘贴您的网址条目以及相应的视图，以便我们更深入地了解问题。