Question

我需要将值从主页内的单元格传递到另一页面。

我必须通过：9.00 Username week year NULL。最后3个在我的数据库中返回0的输入中定义。前2名返回null。所有这些值应该在主页面中已知，因此用户不必插入任何内容。

用户名甚至在主页面之前打印。输入需要用户采取某种行动吗？如果是这样（可以解释0和// First cell form to pass data to booking.php <?php $week = date("W"); $year = (isset($_GET['year']))?$_GET['year']:date("Y"); $week = (isset($_GET['week']))?$_GET['week']:Date('W'); if($week>52){ $year+= 1; $week=1; }elseif($week < 1) { $year--; $week = 52; } ?> <a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week-1).'&year='.$year; ?>">Pre Week</a>  <a href="<?php echo $_SERVER['PHP_SELF'].'?week='.($week+1).'&year='.$year; ?>">Next Week</a>  <table border="1px" class="WeekLayout"> <tr> <td>Schedule</td> <?php if($week < 10) { $week = '0'. $week; } for($day=1; $day<=7; $day++) { $d = strtotime($year."W".$week.$day); echo "<td>".date('l',$d )."<br>"; echo date('d M Y',$d)."</td>"; } ?> </tr> <form action="Booking.php" method="POST" name="BookingForm" id="BookingForm"> <tr class="9"> <td>9.00 </td> <td class="free" onclick="Change(this)"><a href=""> </a> <input type="hidden" name="Monday"> <input type="hidden" name="9.00"></td> <td class="free" onclick="Change(this)"><a href=""></a></td> <td class="free" onclick="Change(this)"><a href=""></a></td> <td class="free" onclick="Change(this)"><a href=""></a></td> <td class="free" onclick="Change(this)"><a href=""></a></td> <td class="free" onclick="Change(this)"><a href=""></a></td> <td class="free" onclick="Change(this)"><a href=""></a></td> </tr> <tr> </table> <input type="hidden" name="$Username"> <input type="hidden" name="$week"> <input type="hidden" name="$year"> <input value="Prenota" type="submit" class="buttonsubmit" id="Prenota"> </form> </div> //Connection to database <?php $user = 'root'; $password = ''; $db = 'elencoprenotazioni'; $host = 'localhost'; $dblink2 = new mysqli($host, $user, $password, $db) or die("Connessione non riuscita: " . mysqli_error()); ?> //Prenotation system <?php include("Connessione2.php"); session_start(); $Username = $_POST['Username']; $week = $_POST['week']; $year = $_POST['year']; $day = $_POST['day']; $hour = $_POST['hour']; $queryinsert = mysqli_query($dblink2, "INSERT INTO calendario (Username, week, year, day, hour) VALUES ('$Username','$week','$year','$day','$hour')"); if($queryinsert) { header("location: index.html"); } mysqli_close(); ?>值）如何在不必让用户插入内容的情况下传递值？

这是代码和一些描述我情况的屏幕。

在我的数据库中这样做我只得到了这个：

正如您所看到的，我得到null表示应该在我的主页面中的值，week表示我在表单中定义的值。

页面的完整视图：

正如您从网址year中看到的那样，我们应该知道Username并且在注销按钮附近打印class WebService{ public static List<user> UserLoglist = new List<user>();//list of logged in users [WebMethod(Description = "Per session Hit Counter", EnableSession = true)] public void ClnUpdateFlag(string un)//gets called via ajax {//Updates the flags i //update users status WebService.UserLoglist.Find(y => y.username == un).isLoggedin = true; } } public class user { public string username; public System.Timers.Timer timScheduledTask = new System.Timers.Timer(); public bool isLoggedin = true; public user(string puser) { username = puser; setimer(); //set server side timer } void Timer1_Tick(object sender, EventArgs e) { ... if (isLoggedin)// window is still open isLoggedin = false; else// user closed the window { ... WebService.UserLoglist.RemoveAll(x => x.username == username);// instance is deleted here ... } } } void setimer() { timScheduledTask.Interval = 3000; timScheduledTask.Enabled = true; timScheduledTask.Start(); timScheduledTask.Elapsed += new System.Timers.ElapsedEventHandler(Timer1_Tick); } }。

Answer 1

为什么在name属性中使用值？

请更改这些......

<input type="hidden" name="Monday">
<input type="hidden" name="9.00"></td>
<input type="hidden" name="$Username">
<input type="hidden" name="$week">
<input type="hidden" name="$year">

到第一个

<input type="hidden" name="day" value="Monday">
<input type="hidden" name="hour" value="9.00"></td>
<input type="hidden" name="Username" name="MyUsername">
<input type="hidden" name="week" name="53">
<input type="hidden" name="year" name="2016">

Form Post方法只将null和0传递给其他页面

1 个答案: