我正在使用Wi-Fi direct
开发Android多人游戏。
使用Wi-Fi直接,我能够在对等设备之间建立连接。此外,代码能够将数据从客户端设备发送到服务器设备。 (根据Android文档,Wi-Fi直接使用客户端 - 服务器模型)
问题:
我无法使用Wi-Fi直接从服务器设备与客户端设备共享数据。
我有以下问题:
(bi-directional)
通过Wi-Fi Direct连接的Android设备?我很感激有关这些查询的任何建议。提前谢谢。
代码: 服务器端
public class DataTransferAsyncTask extends AsyncTask<Void,Void,String>{
ServerSocket serverSocket;
Socket client;
InputStream inputstream;
Context context = mActivity.getApplicationContext();
String s;
InetAddress client_add;
@Override
protected String doInBackground(Void... voids) {
try{
serverSocket = new ServerSocket(9999);
Log.e("hello", "Server: Socket opened");
client = serverSocket.accept();
Log.e("hello", "Server: connection done");
inputstream = client.getInputStream();
// OutputStream outputStream = serverSocket.getO
//getting data from client
byte[] address = new byte[12];
if(client.isConnected())
inputstream.read(address);
s = new String(address);
String only_add = new String();
only_add = s.substring(0,12);
client_add = InetAddress.getByName(only_add);
Log.e("hello", "Server: clients ip 1 " + only_add);
Log.e("hello", "Server: converted address 1 " + client_add + " \n is connected"+
client.isConnected());
//send data to client
OutputStream stream = client.getOutputStream();
stream.write(s.getBytes());
Log.e("hello","context value "+context);
// cancel(true);
}catch (IOException e){
}
return null;
}
}
客户端:
@override
protected void onHandleIntent(Intent intent) {
Log.e("hello","client socket");
Toast.makeText(this,"client socket",Toast.LENGTH_LONG).show();
Context context = getApplicationContext();
if(intent.getAction().equals(action_send_data)){
String host = intent.getStringExtra(group_owner_address);
Socket socket = new Socket();
int port = intent.getIntExtra(group_owner_port,9999);
//binding connection
try{
String x="hello";
Log.e("hello","opening client socket");
byte[] address = getLocalAddress();
String ipAdd = getDottedDecimalIP(address);
socket.bind(null);
socket.connect(new InetSocketAddress(host,port),socket_timeout);
Log.e("hello","device socket address "+ socket.getInetAddress() );
Log.e("hello","client socket is connected"+socket.isConnected());
Log.e("hello","device address :"+ipAdd + " byte "+ address);
//sending data to server
OutputStream stream = socket.getOutputStream();
stream.write(ipAdd.getBytes());
//getting data from the server(supposed to)
InputStream inputstream = socket.getInputStream();
byte[] address_to_sto_fr_ser = new byte[15] ;
inputstream.read(address_to_sto_fr_ser);
String s = new String(address_to_sto_fr_ser);
Log.e("msg from server","msg from server "+s);
// stream.close();
// is.close();
}catch (IOException e){
}
}
}
答案 0 :(得分:2)
客户端与WiFi Direct Group Owner之间的通信基于在Group Owner上运行的Socket服务器和连接到该服务器的客户端。
一旦形成WiFi Direct组(您可以通过检查&#34; onConnectionInfoAvailable(WifiP2pInfo wifiP2pInfo)&#34;)知道,检查当前设备是否为组所有者,如果是,则启动套接字服务器(类似到你的代码):
mServerSocket = new ServerSocket(mPort);
Log.e(getClass().getSimpleName(), "Running on port: " + mServerSocket.getLocalPort());
接下来,添加此行以接受连接并存储客户端套接字的引用:
Socket mSocket = mServerSocket.accept();
现在,您有一个客户端套接字的引用,您可以使用它来向它发送数据/消息。接下来,其他设备(客户端)应该启动与套接字服务器的连接:
mSocket = new Socket();
mSocket.bind(null);
mSocket.connect(new InetSocketAddress(mAddress, mPort), 500);
从服务器向客户端发送消息:
DataOutputStream mDataOutputStream = new DataOutputStream(mSocket.getOutputStream());
发送简单信息:
mDataOutputStream.writeUTF(message);
mDataOutputStream.flush();
希望这有帮助。