尝试使用链表在C#中创建迷宫。无法弄清楚如何开始游戏

时间:2016-12-08 07:13:53

标签: c# maze

我创建了列表和课程' Rooms'。我已将房间添加到列表中。现在我坚持编码游戏本身。基本上我想从A房开始,只能通过按(S)outh按钮到房间E和(W)est按钮到房间B等等,从房间A到房间E和房间B进行迭代。 此外,我正在考虑为游戏调用另一个类,因此代码可以读取。因此,main将只有几行代码。 这是我的代码。无论如何,请随时指出如何优化它。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication2
{
class Program
{
    static void Main(string[] args)
    {
        roomsList theRooms = new roomsList();
        theRooms.allRoomsList();
        theRooms.addRoomToEnd("A");
        theRooms.addRoomToEnd("B");
        theRooms.addRoomToEnd("C");
        theRooms.addRoomToEnd("D");
        theRooms.addRoomToEnd("E");
        theRooms.addRoomToEnd("F");
        theRooms.addRoomToEnd("G");
        theRooms.addRoomToEnd("H");
        theRooms.addRoomToEnd("I");
        theRooms.addRoomToEnd("J");
        theRooms.addRoomToEnd("K");
        theRooms.addRoomToEnd("L");
        Console.WriteLine("What is your name?");
        string playerName = Console.ReadLine();
               Console.WriteLine("================================================================");
        Console.WriteLine(playerName + " You have been Chosen, Enter if you dare!!");
          Console.WriteLine("================================================================");
        Console.WriteLine("(Y)es/(N)o");
        string decision = Console.ReadLine();

        if (decision == "y")
        {
            Console.WriteLine("You need to make you way to Room L, so you may live!!");

        }
        else
        {
            Console.WriteLine("Goodbye");
        }

    }
}
class rooms //create class rooms
{
    private string roomname;
    private rooms next;

    public rooms(string rname) //constructor
    {
        roomname = rname;
        next = null;
    }
    public void setRoom (rooms nxtRoom)
    {
        next = nxtRoom;
    }
    public rooms ftchNext()
    {
        return next;
    }
    public string ftchName()
    { 
        return roomname;
    }
}//done creating class rooms
class roomsList //create linked list
{
    public rooms start, end;
    public roomsList()
    {
        start = null;
        end = null;
    }
    public void addRoomToEnd(string rname)
    {
        rooms current = new rooms(rname);
        if (end == null)
        {
            start = current;
            end = current;
        }
        else
        {
            end.setRoom(current);
            end = current;
        }
    }
    public void allRoomsList()
    {
        rooms current;
        if (start != null)
        {
            current = start;
            while (current != null)
            {
                current = current.ftchNext();
            }
        }
        else { }
    }
}//class list ends

}

1 个答案:

答案 0 :(得分:5)

总体而言,看起来您处于正确的轨道,但缺少一些关键功能。您可以使用以下几点来完成实施

首先,问题陈述,正如我从你的问题中理解的那样:你的迷宫是一个房间的集合。您可以通过向北,向南,向东或向西移动房间。当你到达一个被定义为出口的房间时,你就完成了迷宫。

房间等级:您的房间应该保留这个概念,即它可以连接到不同的房间。我建议如下:

class Room 
{
   public string Name;
   public Room NorthRoom;
   public Room SouthRoom;
   public Room EastRoom;
   public Room WestRoom;
   pulic bool isExit;

   public ConnectTo(Room room, Direction direction)
   {
       // Add room connection logic here...
   }
}

迷宫课程:迷宫课程有一个起始室,就是这样。要创建迷宫,您将创建房间并根据需要在它们之间进行连接。

class Maze
{
   public Room StartingRoom;
}

那我们怎样才能创造一个迷宫呢?我将展示一种天真的方式,但是在这里您可以编写一些辅助函数来使您更容易。

//Lets say we want to have the following maze:
//
// start - room 1 - room 2
//           |        |
//         room 3   room 4 (exit) 

var maze = new Maze();
var startingRoom = new Room();
maze.StartingRoom = startingRoom;
var room1 = new Room();
var room2 = new Room();
var room3 = new Room();
var room4 = new Room();
room4.IsExit = true;
startingRoom.ConnectTo(room1, "East");
room1.ConnectTo(room2, "East");
room1.ConnectTo(room3, "South");
room2.ConnectTo(room4, "South");

要实现连接,请检查您获得的输入方向并设置适当的房间(北,南等)。

玩游戏:在您的主要课程中,在用户同意开始之后,有一个while循环,当用户进入具有IsExit = true的房间时,该循环将停止。您可以跟踪用户所在的当前房间。他们从迷宫的开始开始。用户选择是否想要N,S,E,W。根据他们的选择,您可以将当前房间分别移动到北,南,东,西房间。您需要处理某些房间可能为空的情况。

希望这能给你足够的思考点来完成你的游戏!