>>> idx = np.argmax(result.ravel()) # ravel to get the 1D maximum point
>>> maxy, maxx = np.unravel_index(idx, data.shape) # get 2D coordinates of idx
答案 0 :(得分:0)
USE master
GO
DECLARE @sql VARCHAR(MAX) =
'
USE [?];
SELECT
DB_NAME(database_id) Database_Name, o.name
, indexname = i.name
, i.index_id
, reads = user_seeks + user_scans + user_lookups
, writes = user_updates
, rows = ( SELECT SUM(p.rows) FROM sys.partitions p WHERE p.index_id = s.index_id AND s.object_id = p.object_id )
, CASE WHEN s.user_updates < 1 THEN 100 ELSE 1.00 * ( s.user_seeks + s.user_scans + s.user_lookups ) / s.user_updates END AS reads_per_write
, ''DROP INDEX '' + QUOTENAME(i.name) + '' ON '' + QUOTENAME(c.name) + ''.'' + QUOTENAME(OBJECT_NAME(s.object_id)) AS ''drop statement''
FROM sys.dm_db_index_usage_stats s
INNER JOIN sys.indexes i ON i.index_id = s.index_id AND s.object_id = i.object_id
INNER JOIN sys.objects o ON s.object_id = o.object_id
INNER JOIN sys.schemas c ON o.schema_id = c.schema_id
WHERE OBJECTPROPERTY(s.object_id, ''IsUserTable'') = 1
AND s.database_id = DB_ID()
AND i.type_desc = ''nonclustered''
AND i.is_primary_key = 0
AND i.is_unique_constraint = 0
AND ( SELECT SUM(p.rows) FROM sys.partitions p WHERE p.index_id = s.index_id AND s.object_id = p.object_id ) > 10000 ORDER BY reads_per_write ASC'
EXEC sp_msforeachdb @sql