如何使用渐变和45度角填充library(RMySQL)
con_str <- "MySQL(), user = 'root', password = '', dbname = 'nepal_statagri', host = 'localhost'" (this is the string I want to pass as a parameter to RScript)
mysqlconnection = dbConnect(con_str)
?
例如,在图片1 中,下面的代码绘制一个正方形并填充蓝色图层(CAShapeLayer()
)。
但是,我如何用蓝色到红色的45度角填充它,如图像2 (即UIColor.blueColor().CGColor
到UIColor.blueColor().CGColor
)?
代码:
UIColor.redColor().CGColor
答案 0 :(得分:29)
为什么不使用具有CAGradientLayer
和startPoint
属性的endPoint
。
你可以这样做:
import UIKit
import PlaygroundSupport
let frame = CGRect(x: 0, y: 0, width: 100, height: 100)
let view = UIView(frame: frame)
PlaygroundPage.current.liveView = view
let path = UIBezierPath(ovalIn: frame)
let shape = CAShapeLayer()
shape.frame = frame
shape.path = path.cgPath
shape.fillColor = UIColor.blue.cgColor
let gradient = CAGradientLayer()
gradient.frame = frame
gradient.colors = [UIColor.blue.cgColor,
UIColor.red.cgColor]
gradient.startPoint = CGPoint(x: 0, y: 1)
gradient.endPoint = CGPoint(x: 1, y: 0)
gradient.mask = shape
view.layer.addSublayer(gradient)
注意:为圆圈添加了贝塞尔曲线路径,因为它可以在没有方形掩码的情况下工作。
答案 1 :(得分:5)
虽然上述解决方案仅在像 45°这样的微小角度上确实有效,但是我的代码却能够将梯度设置为任意给定角度。
public extension CALayer {
public func applyGradient(of colors: UIColor..., atAngle angle: CGFloat) -> CAGradientLayer {
let gradient = CAGradientLayer()
gradient.frame = frame
gradient.colors = colors
gradient.calculatePoints(for: angle)
gradient.mask = self
return gradient
}
}
public extension CAGradientLayer {
/// Sets the start and end points on a gradient layer for a given angle.
///
/// - Important:
/// *0°* is a horizontal gradient from left to right.
///
/// With a positive input, the rotational direction is clockwise.
///
/// * An input of *400°* will have the same output as an input of *40°*
///
/// With a negative input, the rotational direction is clockwise.
///
/// * An input of *-15°* will have the same output as *345°*
///
/// - Parameters:
/// - angle: The angle of the gradient.
///
public func calculatePoints(for angle: CGFloat) {
var ang = (-angle).truncatingRemainder(dividingBy: 360)
if ang < 0 { ang = 360 + ang }
let n: CGFloat = 0.5
let tanx: (CGFloat) -> CGFloat = { tan($0 * CGFloat.pi / 180) }
switch ang {
case 0...45, 315...360:
let a = CGPoint(x: 0, y: n * tanx(ang) + n)
let b = CGPoint(x: 1, y: n * tanx(-ang) + n)
startPoint = a
endPoint = b
case 45...135:
let a = CGPoint(x: n * tanx(ang - 90) + n, y: 1)
let b = CGPoint(x: n * tanx(-ang - 90) + n, y: 0)
startPoint = a
endPoint = b
case 135...225:
let a = CGPoint(x: 1, y: n * tanx(-ang) + n)
let b = CGPoint(x: 0, y: n * tanx(ang) + n)
startPoint = a
endPoint = b
case 225...315:
let a = CGPoint(x: n * tanx(-ang - 90) + n, y: 0)
let b = CGPoint(x: n * tanx(ang - 90) + n, y: 1)
startPoint = a
endPoint = b
default:
let a = CGPoint(x: 0, y: n)
let b = CGPoint(x: 1, y: n)
startPoint = a
endPoint = b
}
}
}
let layer = CAShapeLayer()
// Setup layer...
// Gradient Direction: →
let gradientLayer1 = layer.applyGradient(of: UIColor.yellow, UIColor.red, at: 0)
// Gradient Direction: ↗︎
let gradientLayer2 = layer.applyGradient(of: UIColor.purple, UIColor.yellow, UIColor.green, at: -45)
// Gradient Direction: ←
let gradientLayer3 = layer.applyGradient(of: UIColor.yellow, UIColor.blue, UIColor.green, at: 180)
// Gradient Direction: ↓
let gradientLayer4 = layer.applyGradient(of: UIColor.red, UIColor.blue, at: 450)
所以我实际上最近才花了很多时间自己回答这个问题。以下是一些示例角度,仅用于帮助理解和可视化顺时针旋转方向。
如果您对我的计算方式感兴趣,我制作了一张桌子,从本质上可视化了 0°- 360°的工作。
答案 2 :(得分:2)
我认为是
shape.startPoint = CGPoint(x: 1.0, y: 0.0)
shape.endPoint = CGPoint(x: 0.0, y: 1.0)
,这是左下角的第一种颜色,左上角是第二种颜色。如果你想要左上角的第一种颜色和左下角的第二种颜色,那么你应该有
shape.startPoint = CGPoint(x: 1.0, y: 1.0)
shape.endPoint = CGPoint(x: 0.0, y: 0.0)
左上角的第一种颜色,右下角的第二种颜色
shape.startPoint = NSMakePoint(x: 0.0, y: 1.0)
shape.endPoint = NSMakePoint(x: 1.0, y: 0.0)
左下角的第一种颜色,右上角的第二种颜色
shape.startPoint = CGPoint(x: 0.0, y: 0.0)
shape.endPoint = CGPoint(x: 1.0, y: 1.0)
答案 3 :(得分:0)