为什么此代码会不断返回401错误?我从这里克隆了它" https://github.com/purplewove/social-media-apis"测试twython功能但是虽然我有我的推特密钥和秘密,但我得到了很多401而不是实际的推文。
我已经习惯了Python 3.5,但这似乎在3.X或2.X中没有任何客户端错误。我正在使用Anaconda软件包,并且已成功安装twython" ed。
代码如下(与来源不变):
'''
social-media-apis
=================
currently just a bit of code for keyword searches using twython
to use, make sure twython is installed and then type:
python filter_terms.py [consumer_key] [consumer_secret] [access_token_key] [access_token_secret] [search_term]
and the script will dump the text from all tweets gleaned from the streaming api containing the search term to standard output.
find consumer_key, consumer_secret, access_token_key, access_token_secret here: dev.twitter.com/apps
'''
#filter_terms.py
from Stream import Stream
import sys
app_key = sys.argv[1]
app_secret = sys.argv[2]
oauth_token = sys.argv[3]
oauth_token_secret = sys.argv[4]
terms = sys.argv[5:]
stream = Stream(app_key, app_secret, oauth_token, oauth_token_secret)
stream.filter_terms(terms)
#Stream.py
from MyStreamer import MyStreamer
class Stream():
def __init__(self, app_key, app_secret, oauth_token, oauth_token_secret):
self.streamer = MyStreamer(app_key, app_secret, oauth_token, oauth_token_secret)
def filter_terms(self, terms):
self.streamer.filter_terms(terms)
#MyStreamer.py
from twython import TwythonStreamer
import sqlite3
import sys
import datetime
class MyStreamer(TwythonStreamer):
'''a simple streamer that prints the text of a tweet to standard output'''
def __init__(self, app_key, app_secret, oauth_token, oauth_token_secret):
TwythonStreamer.__init__(self, app_key, app_secret, oauth_token, oauth_token_secret)
def on_success(self, data):
if 'text' in data:
print (data['text'])
def on_error(self, status_code, data):
print(status_code)
def filter_terms(self, terms):
'.'.join(terms)
self.statuses.filter(track = terms)
答案 0 :(得分:0)
我重新生成了密钥并且工作正常。每次更换机器时都需要这样做。不确定问题是什么......