我需要同步运行以下异步代码:
using (var httpClient = new System.Net.Http.HttpClient())
{
var stream = GetStreamAsync(url);
StreamReader reader = new StreamReader(url);
jsonString = reader.ReadToEnd();
}
完整的代码看起来:
protected override void OnCreate(Bundle savedInstanceState)
{
base.OnCreate(savedInstanceState);
SetContentView(Resource.Layout.anim_layout);
Animation myAnimation = AnimationUtils.LoadAnimation(this, Resource.Animation.MyAnimation);
ImageView myImage = FindViewById<ImageView>(Resource.Id.imageView1);
myImage.StartAnimation(myAnimation);
FindViewById<Button>(Resource.Id.button1).Click+=delegate
{
StartActivity(new Intent(this, typeof(MainActivity)));
};
}
public string dataByCity(string city)
{
var url = "http://api.openweathermap.org/data/2.5/weather?q=" + city + "&units=metric&APPID=" + AppID;
//ТОРМОЗИТ ЗДЕСЬ / BRAKES HERE
FetchAsync(url);
return city;
}
public double Data_down(double lat, double lon)
{
var url = String.Format(
"http://api.openweathermap.org/data/2.5/weather?lat=" + lat + "&lon=" + lon + "&units=metric&APPID=" + AppID);
//ТОРМОЗИТ ЗДЕСЬ / BRAKES HERE
FetchAsync(url);
return lat;
}
private void FetchAsync(string url)
{
string jsonString;
using (var httpClient = new System.Net.Http.HttpClient())
{
var stream = GetStreamAsync(url);
StreamReader reader = new StreamReader(url);
jsonString = reader.ReadToEnd();
}
var json = jsonString;
StartActivity(new Intent(this, typeof(MainActivity)));
JsonValue firstitem = json;
var mydata = JObject.Parse(json);
cityTextGlobal = (mydata["name"]).ToString();
string GovnoData = (mydata["main"]).ToString();
//spliting string
string[] values = GovnoData.Split(',');
for (int i = 0; i < values.Length; i++)
{
values[i] = values[i].Trim();
if (i == 0)
{
//tempGlobal = values[i];
GovnoTemperature = values[i];
}
}
tempGlobal = null;
foreach (char c in GovnoTemperature)
{
if (c == '.')
{
break;
}
if (c == '-' || char.IsDigit(c) == true || c == '.')
{
tempGlobal += c.ToString();
}
}
// startAct();
//return jsonString;
}
答案 0 :(得分:0)
首先,我想指出以下答案:How would I run an async Task<T> method synchronously?
由于不鼓励仅限链接的答案,因此您可以尝试以下提到的一些内容:
BlahAsync().GetAwaiter().GetResult()
答案 1 :(得分:0)
让您的FetchAsync异步,然后您可以等待它。代码如下:
using (var httpClient = new HttpClient())
{
var response = await httpClient.GetAsync(uri);
string tx = await response.Content.ReadAsStringAsync();
}