我已成功加载python脚本文件,并在C ++应用程序中使用boost::python
调用函数。
在boost python EmbeddingPython wiki中,有how to load a python module提示。
namespace bp = boost::python;
bp::object import(const std::string& module, const std::string& path, bp::object& globals)
{
bp::dict locals;
locals["module_name"] = module;
locals["path"] = path;
bp::exec("import imp\n"
"new_module = imp.load_module(module_name, open(path), path, ('py', 'U', imp.PY_SOURCE))\n",
globals,
locals);
return locals["new_module"];
}
我可以成功地使用它来导入python模块(test.py
)
int main()
{
Py_Initialize();
bp::object main = bp::import("__main__");
bp::object globals = main.attr("__dict__");
bp::object module = import("test", "test.py", globals);
bp::object run = module.attr("run");
run();
return 0;
}
使用 hello-world test.py
脚本运行上述代码可以正常工作:
test.py:
def run():
print "hello world"
输出:
hello world
但是,我现在想要将C ++类暴露给该脚本。
struct Foo
{
void f() {}
};
根据boost::python
文档,我公开了这个类,如下所示:
BOOST_PYTHON_MODULE(FooModule)
{
bp::class_<Foo>("Foo")
.def("f", &Foo::f)
;
}
根据上述链接维基中的说明,我可以导入FooModule
,并将其存储在我的globals
中:
PyImport_AppendInittab("FooModule", &initFooModule);
...
bp::object Foo = bp::import("FooModule");
globals["Foo"] = Foo;
此导入已完成之前以导入我的test.py
脚本,此globals
对象是导入我的脚本时传递给bp::exec
的对象(即: Foo
应该在导入时bp::exec
向我的脚本公开的全局字典中。
但是,出于某种原因,我的Foo
模块不对test.py
如何将我的Foo
类公开给我正在加载的test.py
python脚本?
test.py
def run():
foo = Foo()
foo.f()
main.cpp
#include <iostream>
#include <boost/python.hpp>
namespace bp = boost::python;
bp::object import(const std::string& module, const std::string& path, bp::object& globals)
{
bp::dict locals;
locals["module_name"] = module;
locals["path"] = path;
bp::exec("import imp\n"
"new_module = imp.load_module(module_name, open(path), path, ('py', 'U', imp.PY_SOURCE))\n",
globals,
locals);
return locals["new_module"];
}
struct Foo
{
void f() {}
};
BOOST_PYTHON_MODULE(FooModule)
{
bp::class_<Foo>("Foo")
.def("f", &Foo::f)
;
}
int main()
try
{
PyImport_AppendInittab("FooModule", &initFooModule);
Py_Initialize();
// get a handle to the globals dict
bp::object main = bp::import("__main__");
bp::object globals = main.attr("__dict__");
// import FooModule, and store it in the globals dict
bp::object Foo = bp::import("FooModule");
globals["Foo"] = Foo;
// import the test script, passing the populated globals dict
bp::object module = import("test", "test.py", globals);
bp::object run = module.attr("run");
// run the script
run();
return 0;
}
catch(const bp::error_already_set&)
{
std::cerr << ">>> Error! Uncaught exception:\n";
PyErr_Print();
return 1;
}
Output
>>> Error! Uncaught exception: Traceback (most recent call last): File "test.py", line 2, in run foo = Foo() NameError: global name 'Foo' is not defined
答案 0 :(得分:4)
不是试图从C ++端向{c}注入FooModule
,而是从C ++端注册PyImport_AppendInittab
模块,然后从Python端注册import
:< / p>
import FooModule
def run():
foo = FooModule.Foo()
foo.f()